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2 years ago

Find the slope help please

Mathematics

2 answers:

larisa86 [58]2 years ago

4 0

Answer:

slope =2

Step-by-step explanation:

use math-way it helps

AysviL [449]2 years ago

4 0

Slope or Gradient = y

$\frac{y2 - y1}{x2 - x1} = \frac{2 - 0}{1 - 0} = 2$

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Name the adjacent angles in the diagram below:

harkovskaia [24]

Hey there!

In this picture, we have many pairs of adjacent angles:

1 and 2

2 and 4

4 and 3

3 and 1

This is because these pairs are being connected by a vertex and a side.

Hope it helps and have a great day!!!

5 0

3 years ago

9.12cm 10.36cm 11.34cm 12.61cm

Vinvika [58]

Tan80 = QR / RS
QR = 5.67 (2)
QR = 11.34

answer

11.34cm

8 0

3 years ago

In October sally drove 560 miles in her car.

torisob [31]

The cost is £79.76. Since the car covers 560 miles and 34.5 miles is travelled by one gallon. So, dividing 560 by 34.5 we get 16.23. Since 1 gallon is 4.55 litres, 16.23 gallons is 73.8465. Now the cost of petrol is £1.08 per litre. So, multiplying 73.8465 by £1.08 we have £79.76

4 0

3 years ago

What is the value of 24x -60

Aleksandr [31]

Answer:

-1440

Step-by-step explanation:

24x -60 = -1440

3 0

3 years ago

Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon

leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = proportion of households that have three cell phones NOT known.

So, Null Hypothesis, $H_0$ : p = 30% {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, $H_A$ : p $\neq$ 30% {means that the actual percentage of households different from 30%}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of households having three cell phones = $\frac{43}{150}$ = 0.29

n = sample of households = 150

So, the test statistics = $\frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }$

= -0.27

The value of z test statistic is -0.27.

Also, P-value of the test statistics is given by;

P-value = P(Z < -0.27) = 1 - P(Z $\leq$ 0.27)

= 1 - 0.6064 = 0.3936

Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0

3 years ago