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Norma-Jean [14]
4 years ago
13

Scientific notation 20,000+3,400,000= an example to would be helpful

Mathematics
2 answers:
Marat540 [252]4 years ago
7 0
Scientific notation means representing something as a number on (0,10) exclusive, with a power of ten.
Example: 47,573,018 would be 4.7573018 x10^7
Your numbers 20,000 and 3,400,000 can be represented as 2x10^4 and 3.4x10^6
You can bring these together by changing them so they have the same power of ten, rounding down.
=> 2x10^4 + 340x10^4 => 342x10^4 => 3.42x10^6
Final answer:
20,000+3,400,000=3.42x10^6
Hope I helped :)
Viefleur [7K]4 years ago
4 0
20 000 is as much as 20 * 1 000, so we can write it as: 20 * 10^3
3 400 000 is as much as 34 * 100 000, so we can write it as: 34 * 10^5

The sum in scientific notation would look like this:

20 * 10^3 + 34 * 10^5

I hope that's what you meant :)
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4 years ago
Please solve this question!!​
GaryK [48]

Answer:  (i) 1/221     (ii) 11/221      (iii) 95/663        (iv) 1/663

<u>Step-by-step explanation:</u>

(i) A deck of cards contains 4 Kings out of 52 total cards

1st draw: 4 Kings out of 52 total cards → 4/52 = 1/13

2nd draw: 3 remaining Kings out of 51 total remaining cards  →  3/51 = 1/17

  <u>1st Draw </u>                   <u>2nd Draw </u>                  <u>Outcome</u>         <u>Probability</u>

 King: P(K) = 1/13        King: P(K₂/K₁) = 1/17     King, King       (1/13) x (1/17) = 1/221

*************************************************************************************************

(ii) A deck of cards contains 4 Jacks, 4 Queens, & 4 Kings out of 52 total cards

1st draw: 12 Face cards out of 52 total cards → 12/52 = 3/13

2nd draw: 11 remaining Face cards out of 51 total remaining cards  →  11/51

<u>1st Draw </u>                 <u>2nd Draw </u>                  <u>Outcome</u>       <u>Probability</u>

 Face: P(F) = 3/13    Face: P(F₂/F₁) = 11/51   Face,Face     (3/13) x (11/51) = 11/221

*************************************************************************************************

(iiI) A deck of cards contains 26 black cards out of 52 total cards but there are 2 black Jacks, 2 black Queens, and 2 black Kings.

1st draw: 20 Black (not Face) cards out of 52 total cards → 20/52 = 5/13

2nd draw: 19 remaining Black (not Face) cards out of 51 total remaining cards  →  19/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                       <u>Outcome</u>   <u>Probability</u>

Black: P(B~) = 5/13   Black: P(B~₂/B~₁) = 19/51    B~,B~    (5/13) x (19/51) = 95/663

*************************************************************************************************

(ii) A deck of cards contains 4 Aces out of 52 total cards

1st draw: 4 Aces out of 52 total cards → 4/52 = 1/13

2nd draw: 1 Queen of Hearts out of 51 total remaining cards  →  1/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                   <u>Outcome</u>         <u>Probability</u>

 Ace: P(A) = 1/13      Qh: P(Qh₂/A₁) = 1/51   Ace,Queen(h)   (1/13) x (1/51) = 1/663

7 0
4 years ago
Solve the system using substitution m=4n+11 -6n+8m=36
olchik [2.2K]
M=4n+11
-6n+8m=36

-6n + 8(4n+11) = 36
-6n + 32n + 88 = 36
26n = 36 - 88
26n = -52
n = -2

m = 4n+11 = 4(-2) + 11 = 3

Answer: (3, -2)
4 0
3 years ago
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Answer: 43

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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