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3 years ago

Can someone solve it plz!!!

Mathematics

1 answer:

Shkiper50 [21]3 years ago

8 0

9514 1404 393

Answer:

y = 0.2·0.5^x

Step-by-step explanation:

An exponential function is generally of the form ...

y = a·b^x

where 'a' is the function value when x=0, and b is the ratio between values for x=1 and x=0.

In the given table, y = 0.2 for x = 0, so a = 0.2.

We find that the value for x = 1 is 0.1, so the value of b is ...

b = 0.1/0.2 = 0.5

Then the exponential function is ...

y = 0.2·0.5^x

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Answer: =2084

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4 years ago

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How could we prove that triangleOEB is congruent to triangleOEA

VMariaS [17]

The perpendicular bisector theorem

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4 years ago

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A coin is tossed 10 times. True or false, and explain: (a) The chance of getting 10 heads in a row is 1/1,024. (b) Given that th

Llana [10]

Answer:

a and b both are true.

Step-by-step explanation:

Given : A coin is tossed 10 times.

To find : True or false, and explain ?

Solution :

(a) The chance of getting 10 heads in a row is $\frac{1}{1024}$

Coin has two face head and tail.

The probability of getting head is $P(H)=\frac{1}{2}$

The probability of getting 10 heads in a row is

$P=(P(H))^{10}$

$P=(\frac{1}{2})^{10}$

$P=\frac{1}{1024}$

The chance of getting 10 heads in a row is $\frac{1}{1024}$ is true.

(b) Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is $\frac{1}{2}$ .

The probability of getting 10 heads in a row is $P_1=(\frac{1}{2})^{10}$

The probability of getting 9 tosses were heads is $P_2=(\frac{1}{2})^{9}$

Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is given by,

$P=\frac{P_1}{P_2}$

$P=\frac{(\frac{1}{2})^{10}}{(\frac{1}{2})^{9}}$

$P=(\frac{1}{2})^{10-9}$

$P=\frac{1}{2}$

Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is $\frac{1}{2}$ is true.

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4 years ago

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Answer:

Step-by-step explanation:

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3 years ago

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3 years ago

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