Answer:
yes sure continue with questions
<span>we have that
the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]
we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]
z1=3[cos 110° + i sin 110°]
cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]
z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is
</span>z1=3[cos 110° + i sin 110°]<span>
</span>z2=3[cos 230° + i sin 230°]
z3=3[cos 350° + i sin 350°]<span>
</span>
Answer:
x=22.5
Step-by-step explanation:
Make a ratio
The names of the triangle help with this.
AB is similar to FG, and AC is similar to FH (the missing side)
6/15 = 9/x
cross multiply
6x=135
divide both sides by 6
x=22.5
Answer:
y - (-3) = -8/5 (x - 2)
Step-by-step explanation:
-3 -5 = -8
2 - (-3) = 5
slope = -8/5
y - (-3) = -8/5 (x - 2)
Answer:
the simplified form is 3/5
Step-by-step explanation:
