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Fittoniya [83]
4 years ago
13

How do you simplify 6+3x^2+2y^2-3-y^2

Mathematics
2 answers:
masya89 [10]4 years ago
7 0
3x^2+y^2+3 ‍♀️☹️eugeygeygeuheuheuhe
Shalnov [3]4 years ago
3 0

Answer:

3x^2+y^2+3

Step-by-step explanation:

6+3x^2+2y^2-3-y^2

3x^2+2y^2-y^2+6-3

3x^2+y^2+6-3

3x^2+y^2+3

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You are going to buy some cable television ads. You can get 20 spots for $1200 or 80 spots for $3200 what is the percentage disc
Lesechka [4]

Answer:

  33 1/3%

Step-by-step explanation:

When you buy 20 ads, the per-ad rate is

  $1200/20 = $60 . . . per ad

When you buy 80 ads, the per-ad rate is

  $3200/80 = $40 . . . per ad

The percentage change to the $60 price is ...

  ((new price) - (original price))/(original price) × 100%

  = ($40 -$60)/$60 × 100% = -20/60 × 100%

  = -1/3 × 100% = -33 1/3%

The higher volume purchase comes with a 33 1/3% discount.

5 0
3 years ago
Read 2 more answers
In the trapezoid ABCD (AB∥CD) point M∈AD, so that AM:MD=3:5. Line L ∥AB and going through point M intersects diagonal AC and leg
siniylev [52]

Answer:

\dfrac{AP}{PC}=\dfrac{3}{5}

\dfrac{BN}{CN}=\dfrac{3}{5}

Step-by-step explanation:

Consider triangles AMP and ADC. In these triangles,

  • angle A is the common angle, so \angle MAP\cong \angle DAC by reflexive property;
  • angles AMP and ADC are congruent as corresponding angles when two parallel lines MP and CD are cut by transversal AD.

Hence, triangles AMP and ADC are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

\dfrac{AM}{AD}=\dfrac{AP}{AC}\\ \\\dfrac{3x}{3x+5x}=\dfrac{AP}{AC}\\ \\\dfrac{AP}{AC}=\dfrac{3}{8}\Rightarrow AP=\dfrac{3}{8}AC\\ \\PC=AC-AP=AC-\dfrac{3}{8}AC=\dfrac{5}{8}AC,

so

\dfrac{AP}{PC}=\dfrac{\frac{3}{8}AC}{\frac{5}{8}AC}=\dfrac{3}{5}

Consider triangles ACB and PCN. In these triangles,

  • angle C is the common angle, so \angle ACB\cong \angle PCN by reflexive property;
  • angles ABC and PCN are congruent as corresponding angles when two parallel lines PN and AB are cut by transversal BC.

Hence, triangles ACB and PCN are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

\dfrac{CP}{AP}=\dfrac{CN}{CB}\\ \\\dfrac{5x}{3x+5x}=\dfrac{CN}{CB}\\ \\\dfrac{CN}{CB}=\dfrac{5}{8}\Rightarrow CN=\dfrac{5}{8}CB\\ \\BN=BC-CN=BC-\dfrac{5}{8}BC=\dfrac{3}{8}BC,

so

\dfrac{BN}{CN}=\dfrac{\frac{3}{8}BC}{\frac{5}{8}BC}=\dfrac{3}{5}

4 0
3 years ago
_÷7 = 3 × 1 I dont know what else to but since the question is too short to post
Afina-wow [57]
_ divided by 7 = 3 * 1.    Just do 7*3=21.     so 21 divided by 7 = 3 * 1
7 0
3 years ago
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I need help please answer asap really important
Oliga [24]

0 - 3.66 + 2 = -1.66

8 0
3 years ago
emmas math teacher drew a triangle that had a 60 degree angle and a 20 degree angle. What is the third angle
Dominik [7]
3rd angle is 100

All Angles of a triangle add together will equal 180
20+60=80
180-80=100
6 0
3 years ago
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