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Fittoniya [83]
4 years ago
13

How do you simplify 6+3x^2+2y^2-3-y^2

Mathematics
2 answers:
masya89 [10]4 years ago
7 0
3x^2+y^2+3 ‍♀️☹️eugeygeygeuheuheuhe
Shalnov [3]4 years ago
3 0

Answer:

3x^2+y^2+3

Step-by-step explanation:

6+3x^2+2y^2-3-y^2

3x^2+2y^2-y^2+6-3

3x^2+y^2+6-3

3x^2+y^2+3

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Which of the following linear inequalities matches the given graph below?
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Answer:

O y > 4

Step-by-step explanation:

The dotted line indicates the line is not part of the inequality, and it is clearly greater than 4.

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2 years ago
Biology if one honeybee makes 1/12 teaspoons of honey during its life time how many homey bees do you need to make1/2 tea spoons
Korolek [52]

Answer:

(1/2) / (1/12)

(1/2) * (12/1) = 12/2 = 6


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3 years ago
Sonia has three bracelets. she wears them all at the same time but in a diffrient order each day how many diffrent bracelet comb
LenaWriter [7]
There are 3 bracelets.
The first bracelet can occupy a position in 3 ways.
The second bracelet can occupy the remaining 2 positions in 2 ways.
The third bracelet can occupy the remaining position in 1 way.
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3*2*1 = 6

Answer: 6
3 0
3 years ago
1. Solve the equation.<br>4(x + 5) = 24<br><br>​
bixtya [17]

Answer:

x=1

Step-by-step explanation:

4(x+5)= 24

4x+20=24

-20 -20

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4x = 4

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4 4

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7 0
4 years ago
Read 2 more answers
If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95​% confident that the d
katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Sample size needed

At least n, in which n is found when M = 0.09

We don't know the proportion, so we use \pi = 0.5, which is when we would need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.09\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.09}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}

n = 118.6

Rounding up

We need a sample size of least 119

6 0
3 years ago
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