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Leni [432]
2 years ago
6

3)

Mathematics
1 answer:
Citrus2011 [14]2 years ago
5 0

Answer:

D)

3* (2 x 8) = 3 * (8 x 2)

Step-by-step explanation:

multiplication distributes over addition.

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This is called the leading term
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What is the slope of the line through (−1,−7) and (3,9)?
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The slope is 4.

Step-by-step explanation:

Point slope form is y-y1 over x-x1. I put the coordinates in like this.

9-(-7) over 3-(-1) so thats 9+7 over 3+1. 16 over 4 is 4.

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A triangle can exist with side lengths 15cm, 22cm, and 35cm.<br> A<br> False<br> B<br> True
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The answer is False maybe

8 0
3 years ago
Use series to verify that<br><br> <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{
SVETLANKA909090 [29]

y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\

\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\

This shows that y' = y is true when y = e^x

-----------------------

  • Note 1: A more general solution is y = Ce^x for some constant C.
  • Note 2: It might be tempting to say the general solution is y = e^x+C, but that is not the case because y = e^x+C \to y' = e^x+0 = e^x and we can see that y' = y would only be true for C = 0, so that is why y = e^x+C does not work.
6 0
3 years ago
Which equation does the graph represent (see picture)
egoroff_w [7]
Y=Mx +b

B is 0 because that’s where the graph intercepts the y axis.

M is found by picking any two points and finding the rise and run because m is equal rise/run

Points of choice: (-2,4) and (2,-4)

=2−1/2−1 = -8/4

m is equal -2

Y= -2X

Look at the picture below to differentiate between positive and negative slopes.

8 0
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