The equation is:
20,000 * e^(0.15 t) = 28,000
e^( 0.15 t ) = 28,000 : 20,000
e^( 0.15 t ) = 1.4
0.15 t = ln 1.4
0.15 t = 0.3365
t = 0.3365 : 0.15
t = 2.24 ≈ 2
Answer:
A ) 2 years.
Answer:
<em>Diameter Length: ( About ) 5.4 km; Option B</em>
Step-by-step explanation:
~ Let us apply the Area of the Circle formula πr^2, where r ⇒ radius of the circle ~
1. We are given that the area of the circle is 22.9 km^2, so let us substitute that value into the area of the circle formula, solving for r ( radius ) ⇒ 22.9 = π * r^2 ⇒ r^2 = 22.9/π ⇒ r^2 = 7.28929639361.... ⇒
<em>radius = ( About ) 2.7</em>
2. The diameter would thus be 2 times that of the radius by definition, and thus is: 2.7 * 2 ⇒ ( About ) 5.4 km
<em>Diameter Length: ( About ) 5.4 km</em>
So if one bit of the length, is half the size of the other bit then we can make the following equation, for x being the length of rope:
x + 2x = 66
3x = 66
x = 22
That is the length, of the smaller one (half the big one), so 2x = 44. Hence d) is your answer.
Hope I helped!
The number is 1. 1 multiplied by 100 gives 100 as answer. Lisa claims that <span>when multiplying any number between 0 and 10 by 100, the product is greater than 100. In this case the answer is equal to 100 not greater than 100.
So this proof shows that Lisa's claim is not correct. </span>
Answer:
Size of |E n B| = 2
Size of |B| = 1
Step-by-step explanation:
<em>I'll assume both die are 6 sides</em>
Given
Blue die and Red Die
Required
Sizes of sets
- 
- 
The question stated the following;
B = Event that blue die comes up with 6
E = Event that both dice come even
So first; we'll list out the sample space of both events
Calculating the size of |E n B|
<em>The size = 3 because it contains 3 possible outcomes</em>
Calculating the size of |B|
<em>The size = 1 because it contains 1 possible outcome</em>
