The answer is 6. you just count the boxes in between the two points
Answer:b and c
Step-by-step explanation:
Answer:

Step-by-step explanation:

You can confirm this by working and expanding backwards:

Hope this helps!
1 root.
The reasoning is the same for your other question except x is positive this time round giving x=8 as your only root.

Change the decimal to fraction

Change the denominators to be the same


Add them up

Simplify