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2 years ago

1) The following expression is a 2x + 3 A) monomial B) binomial C)trinomial

Mathematics

2 answers:

motikmotik2 years ago

5 0

Answer:

it is C

Step-by-step explanation:

that is the answer because

Three expression are there which makes it a trinomial

also because

Trinomial: An algebraic expression of three non-zero terms only is called a trinomial. Examples of trinomial: x + y + z is a trinomial in three variables x, y and z. 2a2 + 5a + 7 is a trinomial in one variables a.

olya-2409 [2.1K]2 years ago

3 0

Answer:

I think it is a binomial

Step-by-step explanation:

trinomial-three terms

Monomial-1 term

Binomial-2 terms

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-3^(-x)-6=-3^x+10<br><br>Solve the equation below for x by graphing plz

vitfil [10]

To graph it, just graph $y=-3^{-x}-6$ and $y=-3^x+10$ and see where they intersect

I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it

hmm
multiply both sides by -1
$3^{-x}+6=3^x-10$
multiply both sides by $3^x$
$3^0+6(3^x)=3^{2x}-10(3^x)$
$1+6(3^x)=3^{2x}-10(3^x)$
minus 1 from both sides and minus 6(3^x) from both sides
$0=3^{2x}-16(3^x)-1$
use u subsitution
$u=3^x$
we can rewrite it as
$0=u^2-16u-1$
now factor
I mean use quadratic formula
for $ax^2+bx+c=0$ $x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$
so for 0=u^2-16u-1, a=1, b=-16, c=-1
$u=\frac{-(-16)+/-\sqrt{(-16)^2-4(1)(-1)}{2(1)}$
$u=8+/-\sqrt{65}$
remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor
$u=8+\sqrt{65}=3^x$
$8+\sqrt{65}=3^x$
if you take the log base 3 of both sides you get
$log_3(8+\sqrt{65})=x$
if you use ln then
$ln(8+\sqrt{65})=xln(3)$
then
$\frac{ln(8+\sqrt{65})}{ln(3)}=x$

8 0

2 years ago

Read 2 more answers

Find cos \theta θ if \sin\theta=-\frac{7}{15} sin ⁡ θ = − 7 15 and falls in quadrant 4

madam [21]

let's recall that on the IV Quadrant the x/cosine is positive and the y/sine is negative, and of course the hypotenuse is just a radius unit and therefore never negative.

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{-7}}{\stackrel{hypotenuse}{15}}\impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases}$

$\bf \pm\sqrt{15^2-(-7)^2}=a\implies \pm\sqrt{176}=a\implies \stackrel{\textit{IV Quadrant}}{+\sqrt{176}=a} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{\sqrt{176}}}{\stackrel{hypotenuse}{15}}~\hfill$

6 0

2 years ago

Can I get some help on these

Rainbow [258]

Number 1.
2x to the second power minus 2x minus 4
Number 2.
2a to the second power minus 3b minus a plus b to the second power.

Hope it helped :)

4 0

2 years ago

Start with the standard formula for the area of a triangle, and rewrite it to solve for the base, b.

solong [7]

Answer:

2A/h = b

Step-by-step explanation:

The formula for area of a triangle is

A = 1/2 bh

Multiply each side by 2

2A = 2*1/2 bh

2A = bh

Divide each side by h

2A/h = bh/h

2A/h = b

4 0

2 years ago

Read 2 more answers

Graph 3x + 4y = -10

cricket20 [7]

First, isolate y on one side to find some information about the graph.

3x+4y=-10
4y=-10-3x
y=(-10-3x)/4

Now find out the x and y intercepts of this equation;

(0)=(-10-3x)/4
4x0=-10-3x
0=-10-3x
3x=-10
x=-10/3 or -3.3333 (x-intercept)

y=(-10-3(0))/4
4y=-10
y=-10/4 or -5/2 = -2.5 (y-intercept)

Plot these points onto your graph and connect the lines.

I have attached a graph below, I'm sorry I couldn't do it on paper.

Hope I helped :)

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3 years ago