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3 years ago

If the pentagon below is to be reflected over the line y=x, what are the new coordinates of the vertices?

Mathematics

1 answer:

Harman [31]3 years ago

8 0

Answer:

K' (-2, -2)

L' (3, -2)

G' (4,0)

H' (3,2)

J' (-2, 2)

Step-by-step explanation:

list all the coordinates of the image, and apply the y=x rule of reflection. The line y=x states that the previous y is now in the x and vice versa.

K(-2, -2)

L(-2, 3)

G(0,4)

H(2,3)

J(2, -2)

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In the equation y = x - 5, the slope is

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Answer:

the slope is x or 1x

Step-by-step explanation:

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3 years ago

Read 2 more answers

Please help if so thank you And explain

Naddika [18.5K]

Answer:

x = 34°

Step-by-step explanation:

Given AC and BD are perpendicular bisectors, we can say that at point E, there are 4 right angles [perpendicular bisectors intersect to create 4 90 degree angles].

Now, if we look at the triangle AED, we know that it is a right triangle, meaning that angle E is a right angle.

Also,

We know sum of 3 angles in a triangle is 180 degrees. Thus, we can write:

∠A + ∠E + ∠D = 180

Note: Angle A and Angle D are just the half part of the diagram. More exactly we can write:

∠EAD + ∠ADE + ∠DEA = 180

Given,

∠EAD = 56

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∠EAD + ∠ADE + ∠DEA = 180

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146 + ∠ADE = 180

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4 years ago

Any Help WOULD BE NIne

Vika [28.1K]

Answer:

N is the correct answer because it is

Step-by-step explanation:

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3 years ago

Classify the following lines as either parallel, intersecting, coincident, or skew. In each case find the measure of the acute a

solong [7]

Answer:

The lines are parallel with an acute angle of 0 degrees.

Missing Information:

The equations of lines are missing which are as follows:

Line 1:

x = 1 - 2t , y = 8 + t, z = 5

Line 2:

x = 2 + 4s , y = -1 -2s, z = 3

Step-by-step explanation:

First, we need to find the direction vectors of both the line, we can write them as:

Direction Vector of line 1 = $D_{1}$ = -2u + 1v + 0w

Direction Vector of line 2= $D_{2}$ =4u -2v+0w

As we can see,

$D_{2}$ =-2 $D_{1}$

such that:

4u -2v+0w= -2(-2u + 1v + 0w)

Since,

$D_{2}$ =-2 $D_{1}$

So the lines are parallel such that θ= 0 degrees. (Which is the acute angle between them)

All the points on line 1 have z-coordinate as 5 (z=5),

All the points on line 2 have z-coordinate as 3 (z=3),

Since the z-coordinate do not match , so the lines are not coincident.

Also as the lines are parallel so they are not intersecting.

8 0

4 years ago