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3 years ago

Can someone please help

Mathematics

2 answers:

Grace [21]3 years ago

5 0

Answer:

the standard form of the given algebraic expression is

$x + x - 2 + 7$

$= 2x + 5$

rodikova [14]3 years ago

4 0

Answer:

x square -5x -14

Step-by-step explanation:

Formula:

X square + (a+b)x +ab

And then substitute...

Hope it helped you.

You might be interested in

1/4 + (-3/4)= -4 1/2 + 2= -8+ (-1 1/8) =

AlekseyPX

1/4+ (-3/4) = -0.5

-4 1/2 +2= -2.5

-8+ (-11/8)= -9.125

4 0

4 years ago

If g=x-9 and if x=15what isg

polet [3.4K]

G = 15-9
g = 6

the answer is g =6

8 0

3 years ago

Read 2 more answers

The age of a father is 2 less than 7 times the age of his son. In 3 years, the sum of their ages will be 52. If the son’s presen

fomenos

Hello,

Let's assume f the age of the father,
s the age of the son.

The age of a father is 2 less than 7 times the age of his son ==> f=7s-2 (1)


In 3 years, the sum of their ages will be 52 ==>(f+3)+(s+3)=52 (2)

(2)==>f+s+6=52
==>f+s=46 (3)
(3) and (1) ==>7s-2+s=46
==>8s=48
==>s=6
f=46-6=40

6 0

3 years ago

Brainliest + 20 pts to whoever helps pls!!

Blizzard [7]

Answer:

Correct option is (a). 60.391 and 101.879; because the test statistic is in a critical region, the test rejects the null hypothesis.

Step-by-step explanation:

A Chi-square test for population variance is used to perform this test.

The standard deviation is, 2.0 minutes.

Then the variance is, 4.0 minutes.

The hypothesis for this test is:

H₀: The population variance of all commute times is equal to 4.0 minutes, i.e. σ² = 4.

Hₐ: The population variance of all commute times is not equal to 4.0 minutes, i.e. σ² ≠ 4.

The test statistic is:

$\chi^{2}_{calc.}=\frac{(n-1)s^{2}}{\sigma^{2}}$

The critical region of this test is defined as:

Reject H₀ if $\chi^{2}_{calc.}$ or $\chi^{2}_{calc.}>\chi^{2}_{(1-\alpha /2), (n-1)}$ .

The degrees of freedom is:

$n-1=81-1=80$

Compute the critical from a Chi-square table.

$\chi^{2}_{\alpha /2, (n-1)}=\chi^{2}_{0.05, 80}=101.879\\\chi^{2}_{(1-\alpha /2), (n-1)}=\chi^{2}_{0.95, 80}=60.391\\$

The test statistic value is, $\chi^{2}_{calc.}=105.8$ .

$\chi^{2}_{calc.}=105.8 > \chi^{2}_{0.05, 80}=101.879$

The null hypothesis is rejected because the test statistic is in the critical region.

Thus, the correct option is (a).

6 0

3 years ago

A man left rs 1,800,000 as inheritance.his heirs are 6 daughters and 2 sons.find the share of each heir

egoroff_w [7]

Answer:$225,000 each

Step-by-step explanation: Assuming that they each get an equal share of the inheritance, there are 8 shares of the inheritance so we divided the $1.8m by 8 which equals $225,000 each.

3 0

2 years ago