
<u>First Train:</u>
Time taken = 9 hours (2pm to 11pm)
Let the speed be x
Distance = Time x Speed = 9x
<u>Second Train:</u>
Time taken = 5 hours (6pm to 11pm)
Speed = x + 48
Distance = Time x Speed = 5(x + 48)
Since both the distance they traveled are the same, we equate the distance to solve for x.
<u>Solve for x:</u>
9x = 5(x + 48)
9x = 5x + 240
4x = 240
x = 60
<u>Find the speed:</u>
x = 60 mph
x + 48= 108 mph
Answer: The spend of the two trains are 60 mph and 108 mph.
Given that a = 2, b = 3, and c = 4.
To evaluate ab+c, we will plug given values as shown below
ab+c
=2*3+4
=6+4
=10
Hence final answer is 10.
Answer:
−6a−12+3a
Step-by-step explanation:
You can put "3 or 4" which is in your multiple choice :)
Answer:
3/4 or .75 qt to paint the 15ft and 8ft wall
Step-by-step explanation: