In the activity, Heavy Flying, we looked at constraints for transporting packages from Careful Calculators and Charlie's

Mathematics

1 answer:

Gala2k [10]3 years ago

5 0

Answer: 500 chicken feed and 200 careful calculators

Step-by-step explanation:

2x+3y=1,600

40x+50y=30,000

those are your first two equations

your first matrix equation for A is 2, 3,40,50 and B is 1,600 and 30,000 when you enter those in your calculator and 500 and 200 should be your result.

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IMPORTANT NEED ANSWER ASAP !!

ELEN [110]

Step-by-step explanation:

mark me as brainlist...........

3 0

3 years ago

Can someone show me the answer and maybe the work

Tatiana [17]

Answer:

Solving the expression \frac{y^2z^{\frac{1}{4}} }{(z^{\frac{1}{2}}.xy^{\frac{3}{2}})^3} we get $\mathbf{\frac{1}{y^{\frac{5}{2} }x^3z^{\frac{5}{4} }}}$

Step-by-step explanation:

We need to solve the expression:

$\frac{y^2z^{\frac{1}{4}} }{(z^{\frac{1}{2}}.xy^{\frac{3}{2}})^3}$

We know the exponent rule: $(a^n)^m = a^{nm}$

$\frac{y^2z^{\frac{1}{4}} }{(z^{\frac{1}{2}}.xy^{\frac{3}{2}})^3}\\\\=\frac{y^2z^{\frac{1}{4}} }{z^{\frac{3}{2}}.x^3y^{\frac{9}{2} }}$

Now, another exponent rule says that: $\frac{a^m}{a^n}=a^{m-n}$

$=\frac{y^{2-\frac{9}{2}} z^{\frac{1}{4}-\frac{3}{2} } }{x^3}\\=\frac{y^{\frac{4-9}{2}} z^{\frac{1-3*2}{4} } }{x^3}\\=\frac{y^{\frac{-5}{2}}z^{\frac{-5}{4} } }{x^3}$

We also know that: $a^{-m}=\frac{1}{a^m}$

= $\frac{1}{y^{\frac{5}{2} }x^3z^{\frac{5}{4} }}$

So, solving the expression \frac{y^2z^{\frac{1}{4}} }{(z^{\frac{1}{2}}.xy^{\frac{3}{2}})^3} we get $\mathbf{\frac{1}{y^{\frac{5}{2} }x^3z^{\frac{5}{4} }}}$

3 0

3 years ago

Evaluate <br> 1/3 ÷ 2/5 =<br> Give your answer as a fraction in its simplest form.

Softa [21]

Answer:

5/6

Step-by-step explanation:

Since 1/3÷2/5 can also be written as 1/3/2/5

So the ÷ can then be converted to × and 2/5 will change to 5/2

So let's solve

1/3×5/2

5/6