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Ad libitum [116K]
2 years ago
6

The morning temperature was at 23.5° F. Later that evening the temperature had dropped to 15.6° F. What was the change in temper

ature?
According to Jake the temperature had a change of -7.9° F.



Is Jake’s answer a true of false statement? Please explain your reasoning for your answer.
Mathematics
1 answer:
salantis [7]2 years ago
3 0

Answer:

Jake's answer is true; the change in temperature is -7.9° F.

Step-by-step explanation:

The change in temperature is the final value minus the initial value. Evening minus the morning.

The final value is 15.6° F, the initial value is 23.5° F.

So 15.6 - 23.5 = -7.9

Jake's answer is true.

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At the toy store, 3 toy cars cost $2.61. How much does it cost to buy 15 toy cars?
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Given that, the expression can be written as.

(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)

By simplifying the above equation,

\dfrac{6c^2+3c}{-4c+2}\div \dfrac{2c+1}{4c-2}

By taking out the common terms from the equation,

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By simplifying the above equation by cancel out the common factors.

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Now, by taking (-1) common from (-2c+1) we get,

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So the given equation (6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2) is equivalent to the expression -3c.

For more details, follow the link given below.

brainly.com/question/1301963.

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