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Anettt [7]
3 years ago
11

Grocery store scales are occasionally checked by inspection agencies for their accuracy in reporting the weights of purchased me

rchandise. Scales are allowed to operate as long as the percent error of their reported weights is within 0.5% of the actual weight measured. If you wanted to purchase 15.0 pounds of flour, what range of weights is the scale allowed to report in order to be compliant with local inspection agency regulations.
Mathematics
1 answer:
nikklg [1K]3 years ago
4 0

Answer:

The range of weights in the scale allowed to report in order to be compliant with local inspection agency regulations is between 14.925 pounds and 15.075 pounds.

Step-by-step explanation:

The weights should be within 0.5% of the actual weight measured.

15.0 pounds

0.005*15 = 0.075

Tolerance of 0.075 pounds

15 - 0.075 = 14.925 pounds

15 + 0.075 = 15.075 pounds

The range of weights in the scale allowed to report in order to be compliant with local inspection agency regulations is between 14.925 pounds and 15.075 pounds.

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What is the simplest form of 7/10 + 1/5
earnstyle [38]
Solutions 

1) Find the least common denominator of 7/10 and 1/5. 
10: 10 
5 : 5 , 10 
The least common denominator is 10. 

2) Make the denominator of 1/5 to 10. Multiply numerator and denominator by 2.

1 x 2 = 2 
5 x 2 = 10

3) New fraction 
7/10 + 2/10 

4) Add 
7+2 = 9 

9/10 is answer 

9/10 can not be simplified. It is already in reduced form. 
  


7 0
3 years ago
Read 2 more answers
The sum of the three interior angles of any triangle equal 180 degrees. One right triangle has one acute angle of 30 degrees.
ELEN [110]

Answer: right triangle is a triangle with one angle equal 90. That being said, the total of all angles = 180. 1 of them is 90 which makes the sum of the 2 acute angles = 90. One acute angle = 30 => the second one = 90 - 30 = 60 degree

Step-by-step explanation:

6 0
3 years ago
Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth
pav-90 [236]

Answer:

\sqrt{13} units

Step-by-step explanation:

The distance formula is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where d is the distance between points (x_1,y_1) and (x_2,y_2). Let (x_1,y_1)\rightarrow(5,1) and (x_2,y_2)\rightarrow(3,4), thus:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(3-5)^2+(4-1)^2}\\\\d=\sqrt{(-2)^2+(3)^2}\\\\d=\sqrt{4+9}\\\\d=\sqrt{13}

Therefore, the distance between points P(5,1) and Q(3,4) is \sqrt{13} units.

8 0
2 years ago
Is this right ? Plz help mee
sasho [114]
6.32 is the final answer! :)
6 0
3 years ago
Read 2 more answers
Let U=5i-9j and V=-8i+8j. find U-V
liraira [26]
U-V\\
5i-9j-(-8i+8j)=0
\\5i-9j+8i-8j=0
\\13i-17j=0 
is your final answer.
5 0
3 years ago
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