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3 years ago

Use multiplication to find three equivalent ratios (8 : 12 ) please help !!

2 answers:

8 0

The key idea here is that if you multiply or divide both numerator and denominator of a fraction by the same number, you'll get an equivalent fraction.

So, starting with 8/12, let's choose three numbers, say 2, 5, and 10.

So, if we multiply both numerator and denominator by the same number, we'll get equivalent fractions.

In the first case, we have

$\dfrac{8\cdot 2}{12\cdot 2}=\dfrac{16}{24}$

In the second case,

$\dfrac{8\cdot 5}{12\cdot 5}=\dfrac{40}{60}$

Finally,

$\dfrac{8\cdot 10}{12\cdot 10}=\dfrac{80}{120}$

larisa86 [58]3 years ago

5 0

Answer:

16:24,

4:6

24:36

Step-by-step explanation:

stay safe

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Batting Average Problem Milt Famey has a baseball batting average of 300, which means that his probability of getting a hit at a

Fofino [41]

Answer:

a) $P(X=0)=(10C0)(0.3)^0 (1-0.3)^{5-0}=0.168$

$P(X=1)=(10C1)(0.3)^1 (1-0.3)^{5-1}=0.360$

$P(X=2)=(10C2)(0.3)^2 (1-0.3)^{5-2}=0.309$

$P(X=3)=(10C3)(0.3)^3 (1-0.3)^{5-3}=0.132$

$P(X=4)=(10C4)(0.3)^4 (1-0.3)^{5-4}=0.028$

$P(X=5)=(10C5)(0.3)^5 (1-0.3)^{5-5}=0.00243$

b) And we know that the expected value for a binomial distribution is given by:

$E(X) = np = 5*0.3= 1.5$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=5, p=0.3)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

$P(X=0)=(10C0)(0.3)^0 (1-0.3)^{5-0}=0.168$

$P(X=1)=(10C1)(0.3)^1 (1-0.3)^{5-1}=0.360$

$P(X=2)=(10C2)(0.3)^2 (1-0.3)^{5-2}=0.309$

$P(X=3)=(10C3)(0.3)^3 (1-0.3)^{5-3}=0.132$

$P(X=4)=(10C4)(0.3)^4 (1-0.3)^{5-4}=0.028$

$P(X=5)=(10C5)(0.3)^5 (1-0.3)^{5-5}=0.00243$

Part b

For this case We want to find the extecped number of hits in the 5 at-bat

And we know that the expected value for a binomial distribution is given by:

$E(X) = np = 5*0.3= 1.5$

6 0

4 years ago

Please help<br> Find the Arc Length of arc b, given the radius is 5 cm.

kumpel [21]

Answer:

Arc length= 180/360 ( 2 pi × 5cm)

180/360 (2 ×22/7×5cm)

18/36=1/2× 2×22/ 7 ×5cm

1×22/7×5cm

22/7×5cm

110/7

=15.715cm

5 0

3 years ago

Write an expression that can be used to multiply 6x198 mentally

RoseWind [281]

Do a mental sum for 6 x 200 (1200) then subtract 6<span>x 2 (12) to give you 1188.</span>

8 0

3 years ago

Read 2 more answers

For the period 1997-2003, the number of eggs y (in billions) produced in the United States can be modeled by the function y=-0.2

Viktor [21]

Answer:

Part a) The approximate years were 1998 and 2008

Part b) The graph in the attached figure

Step-by-step explanation:

Part a) we have

$y=-0.27x^{2}+3.3x+77$

For $y=80\ billion\ eggs$

Solve the quadratic equation

$80=-0.27x^{2}+3.3x+77$

$0.27x^{2}-3.3x+3=0$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$0.27x^{2}-3.3x+3=0$

$a=0.27\\b=-3.3\\c=3$

substitute in the formula

$x=\frac{3.3(+/-)\sqrt{-3.3^{2}-4(0.27)(3)}} {2(0.27)}$

$x=\frac{3.3(+/-)\sqrt{7.65}} {0.54}$

$x=\frac{3.3(+)\sqrt{7.65}} {0.54}=11.23\ years$

$x=\frac{3.3(-)\sqrt{7.65}} {0.54}=0.99\ years$

therefore

The approximate years are

1997+11=2008

1997+1=1998

Part b)

Using a graphing tool

we have

$y=-0.27x^{2}+3.3x+77$

$y=80$

The solution of the system of equations is the intersection point both graphs

The intersection point are (0.99,80) and (11.23,80)

see the attached figure

therefore

The solution part a) is correct

3 0

4 years ago

The image shows a reconstruction of a pyramid with a square base. What is the best estimate for the volume of the pyramid?

Anni [7]

Volume of pyramid = 1/3 * 52900 * 138 = 2,433,400 Area of a pyramid is 1/3 * Area of base * height.

From the given pyramid, Area of square base = s^2 = 230^2 = 52900 and the height is 138 meters.

Volume of pyramid = 1/3 * 52900 * 138 = 2,433,400 m^3

hoped this helped

7 0

3 years ago