Answer:
The answer is 1 or infinite solutions
Step-by-step explanation:
When you plug in the value of -5.5 into the equation, you will eventually end up with -17.5=-17.5, making the answer infinite or 1.
Yes... indeed it is 1/8 because
125/1000 In simplest form is 1/8
Answer:
Approximately mMK is 53 degrees
Step-by-step explanation:
Here, we want to find the length of MK
As we can see, we have a right triangle at LNK
so
let us find the angle at L first
9 is adjacent to the angle at L and also, 15 is the hypotenuse of the angle at L
so the trigonometric identity that connects adjacent to the hypotenuse is the cosine
It is the ratio of the adjacent to the hypotenuse
So;
cos L = 9/15
L = arc cos (9/15)
L = 53.13 degree
Approximately, L = 53 degrees
so now, we want to get the arc length MK
We are to use the angle-arc relationship here
Using this; arc length MK is equal to the measure of L at the center which is 53 degrees
Do you want 5 and 6 or just 5? 5 is kind of neat.
44.5% = 0.445
4/9 = 0.4444444
You have enough information to put the numbers in order.
0.44 is the smallest number.
0.44444444.... is the next smallest number
0.4445 is bigger than the number above. 5 is in the ten thousandths place. that is bigger than 4 in the thousands place of 4/9
Finally the largest number of all is 0.445 for the same reason given above.
Six
5/12 = 0.416666
0.4
42% = 42/100 = 0.42
0.416
0.4 is the smallest number
0.416 is the next smallest number
0.41666666 is bigger than 0.416 because you are adding a bunch of 6s onto the decimal place.
The largest one is 0.42. You can put these into your calculator to verify the results. For example, 0.42 - 0.4166666 = 0.003344. Any result more than 0 will show that the first number is bigger than the second.
1/3^-2
You flip the denominator and the numerator to make the 3^-2 positive.
3^2/1= 3^2= 9
1/2^-3
2^3/1= 2^3= 8
I can already tell you that the negative exponents are not going to be as high in value.
3^-2= 1/3^2= 1/9
2^-3= 1/2^3= 1/8
1/3^-2 (the first option) <=== the highest in value
I hope this helps!
~kaikers
