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aksik [14]
2 years ago
8

A class has 6 boys and 15 girls. What is the ratio of boys to girls? Example 2​

Mathematics
2 answers:
Travka [436]2 years ago
7 0

Answer:

Simplified: 6/15 = 2/5

Step-by-step explanation:

Nataly_w [17]2 years ago
5 0

Answer:

6:15 (6 to 15)))))))))))))))))))))

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Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

tinyurl.com/wpazsebu

8 0
2 years ago
Does Cos (x+y)=cosx+cosy? Or not?
dangina [55]
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sin({{ \alpha}} - {{ \beta}})=sin({{ \alpha}})cos({{ \beta}})- cos({{ \alpha}})sin({{ \beta}})
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4 0
3 years ago
Zair has 48 marbles in his pocket. He has 3 more blues than the
d1i1m1o1n [39]

Answer:

# yellow = 20

# blue = 23

# red = 5

Step-by-step explanation:

let 'r' = # red marbles

let '4r' = # yellow marbles

let '3+4r' = # blue marbles

r + 4r + 3 + 4r = 48

9r + 3 = 48

9r = 45

r = 5

red = 5

yellow = 4(5) = 20

blue = 3+4(5) = 23

6 0
2 years ago
Solve for x in the equation x^2 - 8x + 40 = 0​
laiz [17]

Answer:

Conclusion : Trinomial can not be factored

Step-by-step explanation:

5 0
2 years ago
A single card is drawn from a standard 52-card deck. Let D be the event that the card drawn is a black card and let F be the eve
tester [92]

Answer:

The indicated probability of P(D \cup F')=\frac{25}{26}

Step-by-step explanation:

Probability of an event E to be;

P(E) = \frac{Number of events within E}{Total number of possible outcomes}

As per the given condition:

Total number of possible outcomes =  52 cards.

Let the event be D and F as follows;

D : Drawn card is a black card

F : Drawn card is a 10 card.    

Then,

From the given condition:

P(D) = \frac{26}{52}   [Out of 52 cards, 26 were black] ,

P(F) = \frac{4}{52}    [Out of 52 cards, there are four  10 cards]

For any two events A and B we always have;

P(A \cup B) = P(A)+P(B)-P(A \cap B)

Now, we have to find the indicated probability:

P(D \cup F')=P(D)+P(F')-P(D \cap F')               ......[1]

First find the P(F');

P(F') =1-P(F) = 1-\frac{4}{52} =\frac{52-4}{52} =\frac{48}{52}

Also, to find P(D \cap F').

We use the formula :

For any event A and B independent variable.

P(A \cap B) =P(A) \cdot P(B)

then;

P(D \cap F') =P(D) \cdot P(F') = \frac{26}{52} \cdot \frac{48}{52} =\frac{24}{52}

Now, substitute these in [1];

P(D \cup F')=\frac{26}{52} +\frac{48}{52} -\frac{24}{52}=\frac{26+48-24}{52} =\frac{50}{52} = \frac{25}{26}

Therefore, the probability of P(D \cup F')=\frac{25}{26}



3 0
3 years ago
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