Answer:


A)what is the probability that the sample mean will be More than 58 pounds
P(x>58)
Formula : 
Substitute the values :


refer the z table
P(x<58)=0.5359
P(X>58)=1-P(x<58)=1-0.5359=0.4641
Hence the probability that the sample mean will be More than 58 pounds is 0.4641
B)what is the probability that the sample mean will be More than 57 pounds
P(x>57)
Formula : 
Substitute the values :


refer the z table
P(x<57)=0.5040
P(X>57)=1-P(x<57)=1-0.5040=0.496
Hence the probability that the sample mean will be More than 57 pounds is 0.496
C)what is the probability that the sample mean will be Between 55 and 57 pound
Formula : 
Substitute the values :


refer the z table
P(x<57)=0.5040
Formula : 
Substitute the values :


refer the z table
P(x<55)=0.4443
P(55<x<57)=P9x<57)-P(x<55) =0.5040-0.4443=0.0597
Hence the probability that the sample mean will be Between 55 and 57 pounds is 0.0597
D)what is the probability that the sample mean will be Less than 53 pounds
Formula : 
Substitute the values :


refer the z table
P(x<53)=0.3783
The probability that the sample mean will be Less than 53 pounds is 0.3783
E)what is the probability that the sample mean will be Less than 48 pounds
Formula : 
Substitute the values :


refer the z table
P(x<48)=0.2358
The probability that the sample mean will be Less than 48 pounds is 0.2358
The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:

- <em>greater than or equal </em>is written as:

- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
Part A:<span> What is the mean of the data? Show your work. (4 points)</span>
Part B:<span> Use your answer from Part A to calculate the mean absolute deviation for the data. Show your work. (6 points)
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You can divide the field into two squares of area 2500 yd^2. The side of each of those will be √2500 = 50 yd.
The dimensions of the field are 50 yd by 100 yd.
Answer:
27.33333... mph
Step-by-step explanation:
Find 1/3 of 20 1/2: 1/3*41/2=41/6
That equals 6.83333...
Now add 20 1/2 and 6.83333 = 27.3333...
Therefore, 27.33333... mph