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Svet_ta [14]
3 years ago
15

Math help pls all 4 questions please

Mathematics
2 answers:
baherus [9]3 years ago
8 0

Answer:

a)32500

b)0.00604

c)2.4×10^6

d)1.47x10-³

Step-by-step explanation:

plz can i get brainliest:)

zvonat [6]3 years ago
4 0
A. 32500
b. 60,400
c. 2.4 x 10 ^ -6
d. 1.47 x 10 ^3
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The Aluminum Association reports that the average American uses 56.8 pounds of aluminum in a year. A random sample of 50 househo
nalin [4]

Answer:

\mu = 56.8

\sigma = 12.1

A)what is the probability that the sample mean will be More than 58 pounds

P(x>58)

Formula : Z=\frac{x-\mu}{\sigma}

Substitute the values :

Z=\frac{58-56.8}{12.1}

Z=0.09917

refer the z table

P(x<58)=0.5359

P(X>58)=1-P(x<58)=1-0.5359=0.4641

Hence the probability that the sample mean will be More than 58 pounds is 0.4641

B)what is the probability that the sample mean will be More than 57 pounds

P(x>57)

Formula : Z=\frac{x-\mu}{\sigma}

Substitute the values :

Z=\frac{57-56.8}{12.1}

Z=0.0165

refer the z table

P(x<57)=0.5040

P(X>57)=1-P(x<57)=1-0.5040=0.496

Hence the probability that the sample mean will be More than 57 pounds is 0.496

C)what is the probability that the sample mean will be Between 55 and 57 pound

Formula : Z=\frac{x-\mu}{\sigma}

Substitute the values :

Z=\frac{57-56.8}{12.1}

Z=0.0165

refer the z table

P(x<57)=0.5040

Formula : Z=\frac{x-\mu}{\sigma}

Substitute the values :

Z=\frac{55-56.8}{12.1}

Z=-0.1487

refer the z table

P(x<55)=0.4443

P(55<x<57)=P9x<57)-P(x<55) =0.5040-0.4443=0.0597

Hence the probability that the sample mean will be Between 55 and 57 pounds is 0.0597

D)what is the probability that the sample mean will be Less than 53 pounds

Formula : Z=\frac{x-\mu}{\sigma}

Substitute the values :

Z=\frac{53-56.8}{12.1}

Z=−0.314

refer the z table

P(x<53)=0.3783

The probability that the sample mean will be Less than 53 pounds is 0.3783

E)what is the probability that the sample mean will be Less than 48 pounds

Formula : Z=\frac{x-\mu}{\sigma}

Substitute the values :

Z=\frac{48-56.8}{12.1}

Z=−0.727

refer the z table

P(x<48)=0.2358

The probability that the sample mean will be Less than 48 pounds is 0.2358

5 0
3 years ago
Five times the sum of a number and 27 is greater than or equal to six times the sum of that
AleksAgata [21]

The complete version of question:

<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>

Answer:

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

Step-by-step explanation:

As the description of the statement is:

'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>

<em />

As

  • <em>Five times the sum of a number and 27  </em>is written as: 5(x + 27)
  • <em>greater than or equal </em>is written as:  \geq
  • <em>six times the sum of that number and 26'  </em>is written as: 6(x + 26)

so lets combine the whole statement:

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

solving

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

<em />5x+135\ge \:6x+156<em />

<em />5x+135-135\ge \:6x+156-135<em />

<em />5x\ge \:6x+21<em />

<em />5x-6x\ge \:6x+21-6x<em />

<em />-x\ge \:21<em />

<em />\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}<em />

<em />\left(-x\right)\left(-1\right)\le \:21\left(-1\right)<em />

<em />x\le \:-21<em />

Therefore,

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

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3 years ago
Find the measure of Angle 3. measure of angle 1 = x measure of angle 2 = x-6
ipn [44]
Part A:<span> What is the mean of the data? Show your work. (4 points)</span>

Part B:<span> Use your answer from Part A to calculate the mean absolute deviation for the data. Show your work. (6 points)

</span>
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3 years ago
The area of a rectangular soccer field is 5000 yd^2. The length of the field is twice the length. Find the dimensions of the fie
harina [27]
You can divide the field into two squares of area 2500 yd^2. The side of each of those will be √2500 = 50 yd.

The dimensions of the field are 50 yd by 100 yd.
4 0
3 years ago
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zmey [24]

Answer:

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Step-by-step explanation:

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