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katen-ka-za [31]
3 years ago
15

8.7 x 10 to the 2nd power

Mathematics
2 answers:
adell [148]3 years ago
7 0

Answer:

870

Step-by-step explanation:

10^2=100. 8.7*100 is 870.

Andrej [43]3 years ago
6 0

Answer:

7,569

Step-by-step explanation:

8.7 × 10= 87

87 squared (to the 2nd power) is 87×87=7,569

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There are 3 consecutive odd integers that sum to -261. what are the integers​
Iteru [2.4K]

-85, -87, -89

Step-by-step explanation:

1. Divide -261 by 3. (Answer is -87)

2. Take the odd integer before it (-85) and the odd integer after it (-89).

4 0
3 years ago
Write the following equation in slope-intercept form.<br> 3x - 2y=5
prisoha [69]

Answer:

y = 3/2x -5/2

Step-by-step explanation:

Slope intercept form is

y = mx+b  where m is the slope and b is the y intercept

3x- 2y = 5

Solve for y

Subtract 3x from each side

3x -3x- 2y =-3x+ 5

-2y = -3x+5

Divide by -2

-2y/-2 = -3x/-2 +5/-2

y = 3/2x -5/2

3 0
3 years ago
A student claims that 2i is the only imaginary root of a polynomial equation that has real coefficients. Explain the student's m
____ [38]

Answer:

The Fundamental Theorem of Algebra assures that any polynomial  f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i

Step-by-step explanation:

1) This claim is mistaken.

2) The Fundamental Theorem of Algebra assures that any polynomial  f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i with real coefficients.

a_{0}x^{n}+a_{1}x^{2}+....a_{1}x+a_{0}

For example:

3) Every time a polynomial equation, like a quadratic equation which is an univariate polynomial one, has its discriminant following this rule:

\Delta < 0\\b^{2}-4*a*c

We'll have <em>n </em>different complex roots, not necessarily 2i.

For example:

Taking 3 polynomial equations with real coefficients, with

\Delta < 0

-4x^2-x-2=0 \Rightarrow S=\left \{ x'=-\frac{1}{8}-i\frac{\sqrt{31}}{8},\:x''=-\frac{1}{8}+i\frac{\sqrt{31}}{8} \right \}\\-x^2-x-8=0 \Rightarrow S=\left\{\quad x'=-\frac{1}{2}-i\frac{\sqrt{31}}{2},\:x''=-\frac{1}{2}+i\frac{\sqrt{31}}{2} \right \}\\x^2-x+30=0\Rightarrow S=\left \{ x'=\frac{1}{2}+i\frac{\sqrt{119}}{2},\:x''=\frac{1}{2}-i\frac{\sqrt{119}}{2} \right \}\\(...)

2.2) For other Polynomial equations with real coefficients we can see other complex roots ≠ 2i. In this one we have also -2i

x^5\:-\:x^4\:+\:x^3\:-\:x^2\:-\:12x\:+\:12=0 \Rightarrow S=\left \{ x_{1}=1,\:x_{2}=-\sqrt{3},\:x_{3}=\sqrt{3},\:x_{4}=2i,\:x_{5}=-2i \right \}\\

4 0
3 years ago
What is the answer to these for problems I really need a lot of help
Sedaia [141]
If you can post a photo zoomed out less so I can see all the numbers in the questions I can help you, but all you need to do is plug in the value for the variable
3 0
4 years ago
Add. Express your answer as a fraction. Do not include spaces in your answer.<br> 5/1/4+15.5
MAVERICK [17]

Answer:

The answer is 20/3/4(without spaces) or 20 3/4.

Step-by-step explanation:

7 0
3 years ago
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