Verify that -tan2x = (2tanx) / (sec^2x - 2)

Mathematics

1 answer:

sashaice [31]4 years ago

8 0

Answer:

Below.

Step-by-step explanation:

- tan 2x = -2tanx / (1 - tan^2x)

Using the identity tan^2x = sec^2x - 1 and substituting for tan^2x:

- tan 2x = -2 tanx / (1 - (sec^2x - 1))

= 2 tanx / ( - 1(sec^2x + 2))

= 2 tan x / (sec^2 x - 2)

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$\huge \rm༆ Answer ༄$

In the given question, the two sides of the given triangles are parallel, so the the two corresponding angles of the Triangles are equal to one another.

Therefore, the Triangles are similar by AA similarity criteria ~

And since they are similar, the ratio of sides of one Triangle will be equal to ratio of corresponding sides of the other Triangle.

that is ~