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Ksivusya [100]
2 years ago
13

A group of 4 students need to share 20 paper clips equally ?

Mathematics
2 answers:
harkovskaia [24]2 years ago
5 0

Answer:

5

Step-by-step explanation:

jolli1 [7]2 years ago
3 0

Answer:

5 because 20/4=5.......

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What is the remainder when the polynomial 7x^2+15x-2 is divided by x+3
andrey2020 [161]
Simplify each term.
7x^2 + 15x - 2/x + 3
Hope this helps! :)
3 0
3 years ago
Angela uses a scanner to make a reduced-size (smaller) copy of a rectangular photo that is 8 inches long and 4 inches wide. The
svet-max [94.6K]

Answer:

The new width = 2 inches

Step-by-step explanation:

Original dimensions of the rectangular photo:

Length : width = 8 inches : 4 inches

Reduced dimensions of the rectangular photo:

Let

x = the new width

Length : width = 4 inches : x inches

Equate both dimensions to get the value of x

Length : width

8 inches : 4 inches = 4 inches : x inches

8 / 4 = 4 / x

Cross product

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6 0
3 years ago
180=2x+y which equation is used to find x
Serggg [28]
180=2x+y
180-y=2x
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3 0
3 years ago
A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m
Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 46\text{ }pounds=x+y        -(i)

      Total weight of copper = 37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }

       \dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702        -(ii)

       Subtracting 34 times first equation from second equation,

34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0
3 years ago
Find the area of the shaded region 6cm 6cm
Mashutka [201]
Hope this helps! the answer is option (A). if you still don’t understand after looking at my solution feel free to clarify ya

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