-3x^2 + 12x -6
a = -3
b = 12
We calculate the vertex "x" value with this formula:
(vertex "x value") = -b / (2*a)
(vertex "x value") = -12 / -6
The vertex "x" value equals the axis of symmetry value.
The axis of symmetry is at x = 2.
Source:
http://www.1728.org/quadr3.htm
Answer:
-2
Step-by-step explanation:
Substitute -8 in place of x and you get (-8+2)/3 or -6/3 which is -2
(x^-3)^ -5x^6=x^(-3· -5x^6)=x^15x^6
A = 1/5
d = T2-T1
d = 1/10 - 1/5
d = 1/10 - 2/10
d = - 1/10
T4 = 1/5 + 3(-1/10)
= 1/5 - 3/10
= 2/10 - 3/10
= - 1/10
