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Bond [772]
3 years ago
12

The distance around the edge of a pond is 88. What is the radius?

Mathematics
1 answer:
Airida [17]3 years ago
8 0

Answer:

radius= 14

Step-by-step explanation:

the distance around the edge is given by = 2πr

  88= 2 (22/7)*r⇒ r= 88*7/44= 14

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What is the rate of change<br> y=x(-3)+8
chubhunter [2.5K]

Answer:

The rate of change is -3

Step-by-step explanation:

The rate of change is the variable multiplied by x to find y

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Find the lateral area of this pyramid whose
Gnom [1K]

The lateral area of the given pyramid is 108 cm².

Any three-dimensional figure's lateral surface area is its side surface area.

In the question, we are asked to find the lateral area of the given pyramid, whose base is a regular hexagon, with a side length of 3 cm, and the slant height of the pyramid is 12 cm.

To determine the lateral area, we determine the area of one lateral face, and then multiply it by the number of lateral faces in the pyramid.

The number of lateral faces = sides of the base = 6 {Since the base is a regular hexagon}.

Area of a lateral face = (1/2)*base*height {Since its a triangle},

or, area of a lateral face = (1/2)*3*12 {Since the base is the side length of the base, and the height is the slant height},

or, area of a lateral face = 18 cm².

Thus, the lateral area of the pyramid = 6 * 18 cm² = 108 cm².

Thus, the lateral area of the given pyramid is 108 cm².

Learn more about lateral areas at

brainly.com/question/12736338

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4 0
2 years ago
A right triangle whose hypotenuse is 3 centimeters long is revolved about one of its legs to generate a right circular cone. Fin
SSSSS [86.1K]

Answer:

The height of the right circular cone when constructed this way is \sqrt3 cm.

The radius of the right circular cone when constructed this way is \sqrt6 cm.

The volume of the right circular cone when constructed this way is 6\sqrt3 \pi cm³.

Step-by-step explanation:

Given that,

A right triangle whose hypotenuse is 3 cm long is revolved .

Then other two legs of the triangle will be radius and height of the cone.

Assume the height and radius of the cone be h and r respectively.

From Pythagorean Theorem :

h²+r²=3²

⇒ r²= 9 - h²

Then the volume of the cone is

V= π r²h

⇒ V= π(9-h²)h                [ ∵ r²= 9 - h²]

⇒V= π(9h - h³)

Differentiating with respect to h

V'=π(9 - 3h²)

Again differentiating with respect to h

V''= π(-6h)

⇒V''= (-6πh)

To maximum or minimum ,we set V'=0

π(9 - 3h²)=0

⇒3h²=9

⇒h²=3

\Rightarrow h=\sqrt3

Now, V''|_{h=\sqrt3}=-6\pi (\sqrt3).

Since at h=\sqrt3,V''<0.

The volume of cone is maximum at h=\sqrt3 cm when constructed this way.

The height of the right circular cone when constructed this way is \sqrt3 cm.

The radius of the right circular cone when constructed this way  r=\sqrt{9-(\sqrt3)^2

   =  \sqrt{9-3}

   =\sqrt6 cm.

The volume of the  right circular cone when constructed this way is

=π r²h

=\pi (\sqrt6)^2\sqrt3

=6\sqrt3 \pi cm³

6 0
3 years ago
Using the digits 0-9, how many numbers can be configured is the number cannot start with 0
tekilochka [14]
99
i hope this helps you out
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The area is (2x + 15) square centimeters.
emmainna [20.7K]

Answer:

Area\:shaded=\frac{3}{5} (2x+15)

Step-by-step explanation:

Let s be the shaded area and u be the unshaded area, then we know that

(1).  \frac{s}{u}=\frac{3}{2}

and

(2).   s+u=(2x+15)

We solve for u in the first equation and get:

u=\frac{2}{3}s

and put this into the second equation and get:

s+\frac{2}{3}s=(2x+15)

s(1+\frac{2}{3} )=(2x+15)

s(\frac{5}{3}  )=(2x+15)

\boxed{s=\frac{3}{5} (2x+15)}

4 0
3 years ago
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