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hichkok12 [17]
3 years ago
5

Adele spent 8 minutes on the phone while routing 2 phone calls. If she routes 4 phone calls, how much time will Adele have spent

on the phone in total? Solve using unit rates.
Mathematics
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

16 minutes

Step-by-step explanation:

Given

Represent minutes with M and Phone calls with P.

When M = 8; P = 2

Required

Determine M when P = 4

First, we need to determine the constant of proportion using:

M = k * P

Where k represents the constant:

8 = k * 2

Divide through by 2

4 = k

k = 4

Solving for M, when P = 4

Substitute 4 for P and 4 for k in M = k * P

M = 4 * 4

M = 16

Hence:

She spent 16 minutes in total

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If an arithmetic progression satisfies U4=7 , U8=15 .Find U10​
Alja [10]

<em>Answer:</em>

<em>U10 = 19</em>

<em>Step-by-step explanation:</em>

<em>The sequence is </em>Ux=(x*2)-1<em />

<em>x is the coefficient to U.</em>

<em>So, </em>U10=(10*2)-1<em />

<em>Which means </em>U10=20-1<em />

<em>Which means </em>U10=19<em />

<em>And there is your answer.</em>

<em>Hope this helps. Have a nice day.</em>

6 0
2 years ago
A customer service phone line claims that the wait times before a call is answered by a service representative is less than 3.3
Vika [28.1K]

Answer:

(A) Yes, since the test statistic is in the rejection region defined by the critical value, reject the null. The claim is the alternative, so the claim is supported.

Step-by-step explanation:

Null hypothesis: The wait time before a call is answered by a service representative is 3.3 minutes.

Alternate hypothesis: The wait time before a call is answered by a service representative is less than 3.3 minutes.

Test statistic (t) = (sample mean - population mean) ÷ sd/√n

sample mean = 3.24 minutes

population mean = 3.3 minutes

sd = 0.4 minutes

n = 62

degree of freedom = n - 1 = 62 - 1 = 71

significance level = 0.08

t = (3.24 - 3.3) ÷ 0.4/√62 = -0.06 ÷ 005 = -1.2

The test is a one-tailed test. The critical value corresponding to 61 degrees of freedom and 0.08 significance level is 1.654

Conclusion:

Reject the null hypothesis because the test statistic -1.2 is in the rejection region of the critical value 1.654. The claim is contained in the alternative hypothesis, so it is supported.

5 0
3 years ago
The numbers of students in the four
Ludmilka [50]

The total number of students in the four classes is 100 students.

<h3>How to compute the value?</h3>

From the information, the numbers of students in the four sixth-grade classes at Northside School are 26, 19, 34, and 21.

Therefore, the total number of students will be:

= 26 + 19 + 34 + 21

= 100

Therefore there are 100 students.

Learn more about numbers on:

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8 0
2 years ago
Solve the equation and show your work please! <br> 3(2y - 0.3) = 19.4 - y
san4es73 [151]

Answer:

y=2.9

Step-by-step explanation:

3(2y - 0.3) = 19.4 - y

6y-0.9=19.4

6y+y-0.9=19.4

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7y/7=20.3/7 (divid each one by seven. that's what /7 means)

y=2.9

5 0
3 years ago
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