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3 years ago

Please help, needed fast

Mathematics

2 answers:

Naya [18.7K]3 years ago

5 0

Answer:

Step-by-step explanation:

6*5

-2*-8

30+16=46

Alik [6]3 years ago

5 0

Answer:

It would be 46

Step-by-step explanation:

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2y=x+6 2y-x=6 how do i solve following the system of equations

Margarita [4]

$2y = x + 6 \\ \\ 1. \: 2y - 6 = x \\ 2. \: x = 2y - 6 \\ \\ \\ 2y - x = 6 \\ \\ 1. \: - x = 6 - 2y \\ 2. \: x = - 6 + 2y \\ 3. \: x = 2y - 6$

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3 years ago

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2 years ago

If the area of the blue square is 144 units2 and the area of the pink square is 1225 units2, then the length of the hypotenuse i

navik [9.2K]

Answer: 37 units

Step-by-step explanation:

$Blue=144units^2$ This also works as the height of the triangle.

$Pink=1225units^2$ This also works as the base of the triangle.

Let's call pink ''a'', and blue ''b''. The side we're looking for ''c'' is the hypothenuse.

To find the values of a and b, use the area formula of a square and solve for a side. In this case, since we're going to need the squared values, this step can be omitted.

$Formula: A=s^2$

$s=\sqrt[]{A}$

Let's work with Blue.

$s=\sqrt[]{144units^2} \\s=12units$

Now Pink.

$s=\sqrt[]{1225units^2}\\s=35units$

So we have a triangle with a base of 35 units and a height of 12 units.

Now let's use the pythagoream's theorem to solve.

$c^2=a^2+b^2\\c=\sqrt[]{a^2+b^2} \\c=\sqrt[]{(12units)^2+(35units)^2}\\c=\sqrt[]{144units^2+1225units^2}\\ c=\sqrt[]{1369units^2}\\ c=37units$

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3 years ago

Point J is on line segment I K ‾ IK . Given J K = x + 6 , JK=x+6, I J = 9 , IJ=9, and I K = 2 x , IK=2x, determine the numerical

denpristay [2]

Answer:21

Step-by-step explanation:

4 0

3 years ago

Is1/10 and 3/33 epuivalant

sveta [45]

3/33 can be reduced to 1/11 by dividing by 3 on the top and bottom.
1/11 is not equal to 1/10. Although they have the same numerator or number on top, 1, they don't have the same number in the bottom.
So they are not equivalent.
Hope this helps.

7 0

3 years ago

Read 2 more answers