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Westkost [7]
3 years ago
8

PLEASE HELP! ILL MARK BRAINLIEST!!

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
5 0
It’s A, -1/4 because at every square it goes down by a fourth
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Find the vertex of the following quadratic function f(x)=x^2+2x+1
Usimov [2.4K]

Answer:

The answer is that the vertex is: (1, 0)

Step-by-step explanation:

Use the "Completing the Square Method":

(x - h)^2 - k = 0, the vertex is (h, -k)

Complete the square:

x^2 + 2x + 1 = 0

x^2 + 2x = -1

(2/2)^2 = 1, add 1 to both sides of the equation.

x^2 + 2x + 1 = -1 + 1

(x + 1)^2 = 0

(x + 1)^2 - 0 = 0 (Just to put a placeholder in for he -k)

The vertex is (1, 0)

3 0
4 years ago
List the perfect squares that are between 25 and 100
Artist 52 [7]
25,36,49,64,81,100. Hope this helps.
5 0
4 years ago
Y = mc014-1.jpgx – 10; (–6, –29)
skad [1K]
Im a little confused help me here

3 0
3 years ago
How to find the vertex of the,quadratic equation m^2-5m-14=0
777dan777 [17]
quadratic\ formula:ax^2+bx+c=0\\\\m^2-5m-14=0\\\\a=1;\ b=-5;\ c=-14\\\\the\ vertex:(p;\ q)\ where\ p=\frac{-b}{2a}\ and\ q=-\frac{b^2-4ac}{4a}\\\\p=\frac{-(-5)}{2\cdot1}=\frac{5}{2}=2.5\\\\q=-\frac{(-5)^2-4\cdot1\cdot(-14)}{4\cdot1}=-\frac{25+56}{4}=-\frac{81}{4}=-20.25\\\\Answer:The\ vetrex\ is\ (2.5;-20.25)
8 0
3 years ago
Please help w/ this question <br><br> image attached
tangare [24]
<h3>Answer:</h3>

17

<h3>Explanation:</h3>

The median segment (HJ = 5x+2) has a length that is the average of the lengths of the other parallel segments, (KL = 4x+1, and NM = 27). Writing this relation as an equation, we have ...

... 5x + 2 = (4x + 1 + 27)/2

... 10x + 4 = 4x + 28 . . . . . . multiply by 2, collect terms

... 6x = 24 . . . . . . . . . . . . . . add -4x-4

... x = 4 . . . . . . . . . . . . . . . . . divide by 6

Then the length of KL is ...

... KL = 4x +1

... = 4·4 +1 = 17

3 0
4 years ago
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