Six and eighty hundred thirty seven thousandths
Answer:
The equation for the object's height s at time t seconds after launch is s(t) = –4.9t2 + 19.6t + 58.8, where s is in meters. When does the object strike the ground.
Step-by-step explanation:
Answer:
104°
Step-by-step explanation:

Value of expression
is 22 .
<u>Step-by-step explanation:</u>
Here we have the following expression to solve :
8÷2*5+(6-4)
⇒ 
⇒
But 8 = 4(2) , So
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore, Value of expression
is 22 .