Answer:
C) There is not sufficient evidence to support the claim that the mean attendance is greater than 523.
Step-by-step explanation:
Let μ be the the average attendance at games of the football team
The claim: the average attendance at games is over 523
Null and alternative hypotheses are:
: μ=523
: μ>523
The conclusion is failure to reject the null hypothesis.
This means that <em>test statistic</em> is lower than <em>critical value</em>. Therefore it is not significant, there is no significant evidence to accept the <em>alternative</em> hypothesis.
That is no significant evidence that the average attendance at games of the football team is greater than 523.
A. ratio of areas = 2^2 /5^2 = 4/25
B 14^2 : 1 = 196:1
C. ratio of perimeters would be sqrt81 = 9 times
Make 2 equations from the question first
x is the number of pints for type 1
y is the number of pints for type 2
The equation
x + y = 120
60% x + 85% y = 65% (x + y)
Solve the equation
From the 2nd equation
0.6x + 0.85y = 0.65(x + y)
0.6x + 0.85y = 0.65x + 0.65y
0.85y - 0.65y = 0.65x - 0.6x
0.2y = 0.05x
y = 4x
From the 1st equation
x + y = 120
x + 4x = 120
5x = 120
x = 24
y = 4x
y = 96
The first type should be 24 pints, the second type should be 96 pints