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-Dominant- [34]
3 years ago
7

Which fraction has a value that's equal to 3⁄4? A. 12⁄16 B. 12⁄12 C. 4⁄3 D. 9⁄16

Mathematics
2 answers:
Rus_ich [418]3 years ago
8 0
The fraction 12/16 has the same .75 value as the fraction 3/4
puteri [66]3 years ago
8 0
3/4 = 0.75

12/16 ÷ 4/4 = 3/4 = 0.75 
12/12 = 1
4/3 = 1 1/3 = 1.333....
9/16 = already simplified = 0.5625

Thus, 12/16 is your answer. 
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2/3 divided by 1/4 in its simplest form
rewona [7]

Answer:

8/3

Step-by-step explanation:

to divide by a fraction multiply the reciprocal

2/3×4

calculate the product

2×4=8

8/3

5 0
3 years ago
Read 2 more answers
Is the following statement true? Explain.
sukhopar [10]

Step-by-step explanation:

We can prove the statement is false by proof of contradiction:

We know that cos0° = 1 and cos90° = 0.

Let A = 0° and B = 90°.

Left-Hand Side:

cos(A + B) = cos(0° + 90°) = cos90° = 0.

Right-Hand Side:

cos(A) + cos(B) = cos(0°) + cos(90°)

= 1 + 0 = 1.

Since LHS =/= RHS, by proof of contradiction,

the statement is false.

4 0
3 years ago
A square sandbox has an area of 75 square feet. Estimate the length of one of the sides of the sandbo
harkovskaia [24]

not understanding what you are saying?

6 0
3 years ago
I need help asap with this
tatyana61 [14]

Answer:

51°

Step-by-step explanation:

Given

<QPR = 39°

<PQR = 90° ( inscribed angle in semi circle)

Now

<QPR + <PQR + <PRQ = 180° { being sum of angles of triangle)

39° + 90° + <PRQ = 180°

<PRQ = 180° - 39° - 90°

<PRQ = 51°

Hope it will help :)

5 0
3 years ago
Q1 [5]
ValentinkaMS [17]

Answer:

The required drawing showing the cliff, river, and tower as well as the details in the question is attached, please find alongside the answer

The width of the river is approximately 51.55 meters

Step-by-step explanation:

The height of the observation tower = 11 meters

The angle of elevation of the cliff top and the opposite side of the river = 20°

The angle of elevation of the tower top and the opposite side of the river = 30°

Therefore, by sine rule, we have;

h/sin(20) = w/sin(60)

11/sin(10) = length, l/sin(60)

l = sin(60) ×11/sin(10) ≈ 54.86 meters

w = l × cos (20) = 54.86 meters × cos (20) ≈ 51.55 meters

The width, w, of the river is approximately 51.55 meters.

5 0
3 years ago
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