The inequality for sec (x) < cot (x) is; π/2 < x < π
<h3>How to express trigonometric inequality?</h3>
We are given that;
We want to find the intervals that the trigonometric inequality sec (x) < cot (x) always hold true.
This can also be expressed as;
1/cos (x) < 1/tan (x)
Now, this can happen only in the quadrant where tan (x) is negative and cos x is positive which is in fourth quadrant where;
π/2 < x < π
The inequality for sec (x) < cot (x) is; π/2 < x < π
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Answer:
45
Step-by-step explanation:
YOU GET THAT BECAUSE YOUR USING EXPONETS
Step-by-step explanation:
ans is $351.271875 of total cost
Answer:
The system of equation y=120+20x and y=30x
Step-by-step explanation:
Let the number of days be x and y be the total number minutes
Jamie has walked 120 mins. She will walk at a rate of 20 mins per day.
y=120+20x
Owen walks 30 mins a day. So
y = 30x
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I think B not 100%shure ,you could prob go ask this on yahoo and get a bit more help ;) sorry I couldent help more