There is nothing there to work with
Add like terms
I'm assuming that you forgot to put the parenthasees at the end
so exg
4x+8x=12x
2x^2+3x^2=5x^2
3x^2+3x^3=3x^2+3x^3
group like tems
6x^3+9x-8+5x-9x^2+7
6x^3-9x^2+14x-1
Answer:
17 k + -25
Step-by-step explanation:
Simplify the following:
-5 (1 - 5 k) - 4 (2 k + 5)
-5 (1 - 5 k) = 25 k - 5:
25 k - 5 - 4 (2 k + 5)
-4 (2 k + 5) = -8 k - 20:
25 k + -8 k - 20 - 5
Grouping like terms, 25 k - 8 k - 20 - 5 = (25 k - 8 k) + (-5 - 20):
(25 k - 8 k) + (-5 - 20)
25 k - 8 k = 17 k:
17 k + (-5 - 20)
-5 - 20 = -25:
Answer: 17 k + -25
Answer:
y = 
Step-by-step explanation:
Let the total numbers are n.
If the average of y numbers is x then we can form an equation
⇒ 
⇒ n = 
--------(1)
Now 30 is added to the set of numbers then average becomes (x - 5)
⇒ 
⇒ (n + 1) = 
⇒ n = - 1 ----- (2)
Now we equate the values of n from equation 1 and 2
= - 1
y(x - 5) = x(y + 30) - x(x - 5) [ By cross multiplication ]
xy - 5y = xy + 30x - x² + 5x
xy - xy - 5y = 35x - x²
-5y = 35x - x²
x² - 35x = 5y
y =
Answer:
x = 24
Step-by-step explanation:
Pythagorean Theorem: a² + b² = c²
<em>a</em> = a leg
<em>b</em> = another leg
<em>c</em> = hypotenuse
Step 1: Plug in known variables
x² + 10² = 26²
Step 2: Evaluate
x² + 100 = 676
Step 3: Isolate <em>x </em>term
x² = 576
Step 4: Isolate <em>x</em>
√x² = √576
x = 24
