Answer:
Standard form: 2c^4 + 6c^2 - c
Degree: 4th
Leading coefficient: 2
Classification: Trinomial
Step-by-step explanation:
In standard form, you have to put the term with the highest exponent first.
With finding the degree, you just look at the highest exponent and that's the degree. 4 is the highest exponent, so it is to the 4th degree.
The leading coefficient is the number attached to the highest exponent. 4 is the highest and the number attached to it is 2.
Classification goes by how many terms there are. Since there are 3, it's trinomial. Tri as in three.
Answer and Step-by-step explanation:
Alright, so when creating any type of math problem, it is important to identify the parts of the problem and where they go. First, we need to start by putting the problem together. We will use one of the most common forms of equations of math, also known as the linear equation of <em>y=mx+b.</em>
So we have: S(w)=__x + __. S(w) is also equal to f(x), which is also equal to y. So: y= __x + __.
Let's start filling this equation in. So, because it says that she will <em>add 25 dollars each week</em>, The problem is addition. Also, the 25 dollars each week will represent the mx in this situation. Here's why:
The x in this can stand for the amount of week she added this 25 dollars to her account. So:
y= 25x + __.
Now, we can add the 150 to the problem because that is what she started with for this one-time deal. So now we have:
y= 25x + 150.
You can now where everything is represented, but we are not done. Let's change y and x back into S(w) and w like the question asks us to have. So:
S(w)= 25w + 150.
If you want to solve this question, just replace the number of weeks in place of all w's in the equation, like this: S(2)= 25(2) + 150.
I hope that this helps.
Answer: one hundred eleven thousandths
Step-by-step explanation:
You need to find a number that all three of those numbers go into. They all go into 60. Then, divide 60 by three because there are three items. 60 divided by 3 is 20, which is the answer.
Answer:
0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x
Step-by-step explanation:
Given the data in the question;
sample size n = 28
slope of the least squares regression line of y on x or sample estimate = 0.0623
standard error = 0.0224
95% confidence interval
level of significance ∝ = 1 - 95% = 1 - 0.95 = 0.05
degree of freedom df = n - 2 = 28 - 2 = 26
∴ the equation will be;
⇒ sample estimate ± ( t-test) ( standard error )
⇒ sample estimate ± ( 
) ( standard error )
⇒ sample estimate ± ( 
) ( standard error )
⇒ sample estimate ± ( 
) ( standard error )
{ from t table; ( ) = 2.055529 = 2.056
so we substitute
⇒ 0.0623 ± ( 2.056 )( 0.0224 )
Therefore, 0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x
