2x^3-2x^2+3x^2-3x-6x+6
2x^3+x^2-9x+6
The number is 4.
<h3>What is the Quotient?</h3>
A quotient is defined as the outcome of dividing an integer by any divisor that can be said to be a quotient. The dividend contains the divisor a specific number of times.
Let n be the number in question; then, we can write the word problem as an equation like this:
⇒ (n/6) + 1/3 = 7/6
Multiply everything by the least common multiple of all the denominators (6, 3, 6), which is 6.
⇒ 6(n/6) + 9(1/3) = 6(7/6)
⇒ n + 3 = 7
Subtract 3 from both sides,
⇒ n = 4
Hence, the number is 4.
Learn more about the quotient here:
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Answer:
they are complementary
Step-by-step explanation:
Its an indirect proof, so 3 steps :-
1) you start with the opposite of wat u need to prove
2) arrive at a contradiction
3) concludeReport · 29/6/2015261
since you wanto prove 'diagonals of a parallelogram bisect each other', you start wid the opposite of above statement, like below :- step1 : Since we want to prove 'diagonals of a parallelogram bisect each other', lets start by assuming the opposite, that the diagonals of parallelogram dont bisect each other.Report · 29/6/2015261
Since, we assumed that the diagonals dont bisect each other,
OC≠OA
OD≠OBReport · 29/6/2015261
Since, OC≠OA, △OAD is not congruent to △OCBReport · 29/6/2015261
∠AOD≅∠BOC as they are vertical angles,
∠OAD≅∠OCB they are alternate interior angles
AD≅BC, by definition of parallelogram
so, by AAS, △OAD is congruent to △OCBReport · 29/6/2015261
But, thats a contradiction as we have previously established that those triangles are congruentReport · 29/6/2015261
step3 :
since we arrived at a contradiction, our assumption is wrong. so, the opposite of our assumption must be correct. so diagonals of parallelogram bisect each other.
A cause u gotta buy a new one instead of used or borrowing it
