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frez [133]
3 years ago
8

PLEASE HELP ME WITH THIS QUESTION:

Computers and Technology
1 answer:
Darina [25.2K]3 years ago
5 0
There’s literally no question here
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If AL contains binary 1000 1111, which one will show the information of the binary bits in AL after performing operation SHR AL,
padilas [110]

Answer:

a) AL will contains 0011 1100

Explanation:

In assembly language, shifting bits in registers is a common and important practice. One of the shifting operations is the SHR AL, x where the x specifies that the bits be shifted to the right by x places.

SHR AL, 2 therefore means that the bits contained in the AL should be shifted to the right by two (2) places.

For example, if the AL contains binary 1000 1111, the SHR AL, 2 operation will cause the following to happen

Original bit =>                                        |   1  |  0 |  0  |  0  |  1 |  1 |  1 |  1 |

Shift once to the right =>                |  1 |   0 |  0  |  0  |  1 |  1 |  1 |  1 | (0) |

Shift once to the right =>          |  1 |  0 |  0  |  0  |  1 |  1 |  1 |  1 | (0) | (0) |

Notice;

(i) that there are two shifts - one at a time.

(ii) that the bits in bold face are the bits in the AL after the shift. Those that in regular face are those in the carry flag.

(iii) that the new bits added to the AL after a shift are the ones in bracket. They are always set to 0.

5 0
3 years ago
5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S
Stells [14]

Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. const keyword restricts us so we cannot make any change to s1 or s2 object as well as the Shape function itself.

5 0
3 years ago
Which of the following items are typically included in a balanced budget A. The amount you earn in income
taurus [48]
D is the correct answer

8 0
3 years ago
What is the answer to 7.4.4: Length of User's Name codehs
Alik [6]

The program that ask the user to type there first name and then print out how many letters that is in there name is as follows:

x = input("what is your first name: ")

y = len(x)

print(f"There are {y} letters in your name")

<h3>Code explanation;</h3>

The code is written in python.

  • Firstly, we store the users name in the variable x.
  • Then, we find the length of the users inputted name and store it in a variable y.
  • Finally, we print the length of the users name using the print function.

learn more on python here: brainly.com/question/26738945

4 0
2 years ago
WHO IS EXCITED FOR COLD WAR SEASON 1????
xxMikexx [17]

Answer:

me  iggggggg

Explanation:

7 0
3 years ago
Read 2 more answers
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