Complete Question:
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?
Answer:
a) 51.2 msec. b) 5.12 msec
Explanation:
If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:
The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:
a) BW = 1 Mbps = 10⁶ bps
⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec
b) BW = 10 Mbps = 10⁷ bps
⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
Answer: For best performance and lowest latency, the MMU and CPU should support hardware ... broadcast, and subnet broadcast traffic with the deny-all catch-all filter rule for ... Please refer to the NetSight Wireless Manager User Guide (v5.1 or higher ) for a ... The rule must also be positioned above the 'Deny All' Default action.
Explanation:
Answer:
B)tracert
Explanation:
Tracery Command can be regarded as
network diagnostic tool, it is used in tracking process of pathway of packet ranging from source to destination on IP network. It as well allows to know real time of each hops that are been taken by a packet as it enroutes to it's destination. The traceroute can be run by following these steps:
✓Open the run window
✓Open Command prompt, this can be done by enter "cmd" then enter.
✓ input" tracert" then destination ( Ip address or web address)
It should be noted that Tracery command issued from the command prompt will show the route that a packet travels from the issuing computer to another computer.
The answer should be: True
