The main difference can be directly observed in the
formulas used to calculate for the margin of error.
For the population mean, the margin of error would simply
be:
<span>MOE = z * s / sqrt(n)
where z is the z-score, s is the standard deviation and n is the number of
samples</span>
For the population proportion, the margin of error is:
MOE = z * sqrt[p (1 – p) / n]
<span>where p is the probability of success </span>
Answer:
hmm maybe 1?
Step-by-step explanation:
Answer:
"The area of EFGH is always One-half of the area of the rectangle."
Step-by-step explanation:
<em>Graph is attached.</em>
<em />
The kite consists of 2 triangle, EFG and EHG.
The area of EFG:
![\frac{1}{2}*EG*h](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2AEG%2Ah)
where h is the height from F to EG
The area of EHG:
![\frac{1}{2}*EG*h_1](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2AEG%2Ah_1)
where
is the height from H to EG
We also know that h + h _1 is the width of the rectangle and EG is the length of the rectangle
Thus,
Area of Kite = ![\frac{1}{2}*EG*h + \frac{1}{2}*EG*h_1 = RectangleLength*RectangleWidth](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2AEG%2Ah%20%2B%20%5Cfrac%7B1%7D%7B2%7D%2AEG%2Ah_1%20%3D%20RectangleLength%2ARectangleWidth)
Also, Area of rectangle is rectangle length * rectangle width.
Thus, area of kite is always half of that of rectangle, the third choice is right.
It is
9,000,000.000 + 30,000.000 + 2,000.000 + 500.00 + 4.000 + .75