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3 years ago

Order the numbers from least to greatest.

Mathematics

2 answers:

Mars2501 [29]3 years ago

7 0

Answer:

4.446 then 4.464 then 5.228

Step-by-step explanation:

Hope this HELPS :D

padilas [110]3 years ago

7 0

4.446, 4.464, 5.228. in

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Write the five term sequence that would represent each recursive rule f(x) = f(x-1) -7; f(2) = 12

barxatty [35]

<u>Answer: </u>

Required five terms of sequence are 19 , 12 , 5 , -2 and -9 .

<u> Solution: </u>

Need to find the five terms of the sequence.

Given recursive rule is f(x) = f(x-1) -7

Substituting x = 2 , f(2) = f(2-1)-7

= f(2) = f(1) – 7 ------(1)

Also given that f(2) = 12.

On substituting the given value of f(2) in eq (1) we get

12 = f(1) – 7

f(1) = 12 + 7 = 19

Using given recursive rule and given value of f(2) calculating f(3)

Substituting x = 3 ,

f(3) = f(3-1) – 7

= f(2) – 7

= 12 – 7

= 5

Using given recursive rule and calculated value of f(3) calculating f(4)

Substituting x = 4,

f(4) = f(4-1) – 7

= f(3) – 7

= 5– 7

= -2

Using given recursive rule and calculated value of f(4) calculating f(5)

Substituting x = 5,

f(5) = f(5-1) – 7

= f(4) – 7

= -2– 7

= -9

Hence required five terms of sequence are 19 , 12 , 5 , -2 and -9 .

8 0

3 years ago

A school picnic your teacher asks you to Market food trip every 10 yards Sullivan students can play football with the teacher ac

Gemiola [76]

1 yard = 0.9144 meters

1 yard * 10 = 0.9144 meters * 10

10 yards = 9.144 meters

9.144 meters

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2 years ago

Clarence saved 19% of the money he earned. If he earned $90, how much did Clarence save?

Tcecarenko [31]

Answer:

probably like 10

Step-by-step explanation:

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2 years ago

30,000 rounded to the nearest thousand. what is the largest number and what is the lowest.

denis23 [38]

30,000 to the nearest thousands. The largest number is 30,499 and the lowest number is 29,500.

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3 years ago

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

3 years ago