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Ivahew [28]
3 years ago
11

Suppose a sample of 1390 suspected criminals is drawn. Of these people, 514 were captured. Using the data, estimate the proporti

on of people who were caught after being on the 10 Most Wanted list. Enter your answer as a fraction or a decimal number rounded to three decimal places.
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer:

The estimate for the proportion of people who were caught after being on the 10 Most Wanted list is of 0.37.

Step-by-step explanation:

Estimate of the proportion of people who were caught after being on the 10 Most Wanted list.

Number of people captured divided by the size of the sample.

We have that:

514 of 1390 people were captured. So

514/1390 = 0.37

The estimate for the proportion of people who were caught after being on the 10 Most Wanted list is of 0.37.

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Answer:

its 50 points but still answer is a

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2 years ago
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For a given IQ test, an individual is considered a genius if their score falls more than three standard deviations from the mean
ki77a [65]

Answer:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

And we can say that the answer is a.2

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu=?,\sigma=?)  

We are interested on this probability

P(X>X+3\mu)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

And we can find the following probablity:

P(Z>3) = 1-P(Z

So then the probability that an individual present and IQ higher than 3 deviation from the mean is 0.00135

And if we find the number of individuals that can be considered as genius we got: 0.00135*1500=2.025

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3 0
3 years ago
Divide (x4 – 11x3 – 49x2 + 899x – 2506) ÷ (x – 8).
pickupchik [31]
Okay first make sure you change negative 8 to a positive 8. 
Set the problem up 8  -11 -49 899 -2506
                                    __________________
8  -11 -49   899    -2506
          -88 -1096    -1576
   ____________________
    -11 -137 -197     -4082

Your answer will be 
-11x^3 - 137x^2 - 197x - 4082
6 0
3 years ago
Use the listing method to represent the following set.
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Answer:

b

Step-by-step explanation:

{x | x I, x ≥ 3}

6 0
3 years ago
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Find the solution of this system of equations. Separate the x- and the y- values with a comma. X=6+y -8x+9y=-29
WINSTONCH [101]

Answer:

x= 25, y = 19

Step-by-step explanation:

Solve the following system:

{x = y + 6 | (equation 1)

9 y - 8 x = -29 | (equation 2)

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Swap equation 1 with equation 2:

{-(8 x) + 9 y = -29 | (equation 1)

x - y = 6 | (equation 2)

Add 1/8 × (equation 1) to equation 2:

{-(8 x) + 9 y = -29 | (equation 1)

0 x+y/8 = 19/8 | (equation 2)

Multiply equation 2 by 8:

{-(8 x) + 9 y = -29 | (equation 1)

0 x+y = 19 | (equation 2)

Subtract 9 × (equation 2) from equation 1:

{-(8 x)+0 y = -200 | (equation 1)

0 x+y = 19 | (equation 2)

Divide equation 1 by -8:

{x+0 y = 25 | (equation 1)

0 x+y = 19 | (equation 2)

Collect results:

Answer:  {x = 25 , y = 19

6 0
3 years ago
Read 2 more answers
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