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Nadya [2.5K]
2 years ago
15

You buy rice at $0.71 a pound a batch requires 4 pounds or rice how much is one batch​

Mathematics
2 answers:
exis [7]2 years ago
4 0

Answer:

$2.84 for one batch

Step-by-step explanation:

$0.71 x 4 = $2.84

Vika [28.1K]2 years ago
3 0

Answer:

$2.84 for one batch

Step-by-step explanation:

I know this how you ask? $0.71 x 4 = $2.84

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The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f
WITCHER [35]

Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

r=12\ cm\\b=12\ cm\\h=12\ cm

substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)\\C=6\pi\ cm

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

Find the perimeter

P=(6\pi+12\sqrt{2})\ cm

simplify

Factor 6

P=6(\pi+2\sqrt{2})\ cm

4 0
3 years ago
Determine the angle at the centre of a circle with radius 12.0 cm for an arc length of of 21.0 cm.
nata0808 [166]

Answer:

\theta=\dfrac{7}{4}\ \text{radian}

Step-by-step explanation:

We have,

Radius of the circle is 12 cm

Arc length, l = 21 cm

It is required to find the central angle of the circle. The formula for the length of an arc of a circle is :

l=r\times \theta

\theta is central angle

\theta=\dfrac{l}{r}\\\\\theta=\dfrac{21}{12}\\\\\theta=\dfrac{7}{4}\ \text{radian}

So, the angle at the centre of the circle is \dfrac{7}{4}\ \text{radian}.

7 0
2 years ago
I need help ,, i don't understand !<br>​
otez555 [7]

Answer: B

Step-by-step explanation: The question is asking for the point greatly different from all the rest, the outlier. Point B is far away from the grouping of all the other points, making it the outlier.

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