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ANTONII [103]
3 years ago
7

Find the value of x in the isosceles triangle shown below. WILL MARK BRAINLIEST

Mathematics
1 answer:
Tresset [83]3 years ago
6 0

Answer:

from now on don't ask same qn two times or more it would be waste of your points

got it??

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The table shows a relationship between the number of pounds of apples and the total cost. Is the relationship proportional?
Mice21 [21]

Answer:

C Yes, because the cost is always three times the number of pounds.

Step-by-step explanation:

Because 2*3=6, 4*3=12, and 8*3=24

7 0
2 years ago
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
3 years ago
Select the correct answer.
Andrew [12]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
5. What is the volume of the pyramid? *
rjkz [21]

Step-by-step explanation:

jawabannya

336 in 3

cuma di kali kali

8×7×6=336

7 0
3 years ago
H/5 &gt; 12<br> What is it true and what is it false
Karolina [17]

Answer:

This statement is false

Step-by-step explanation:

5 is less than 12 so it should be written like this

5 < 12

Alligator mouth faces the larger numbers

7 0
3 years ago
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