Answer:
The answer is false
Step-by-step explanation:
In a sample above 30 obs like this the confidence interval is defined as
X+- t* (s/sqrt(n)) where X is the mean t the tvalue for a given confidence level, n the size of sample and s standar deviation.
To find de appropiate value of t we must see the T table where rows are degrees of freedom and columns significance level
The significance is obtained:
significance = 1 - confidence level = 1 - 0.9 = 0.10
Degrees of freedom (df) for the inteval are
df = n - 1 = 18 - 1 = 17
So we must look for the value of a t with 17 values and significance of 0.10 which in t table is 1.740 not 1.746 ( thats the t for 16 df)
Answer:
i think its 21/x-4
Step-by-step explanation:
sorry if im wrong
Answer:
-9x^3+4x^2+5
Step-by-step explanation:
(6x^2 - 3 - 5x^3) - (4x^3 +2x^2 - 8)
distribute the minus sign
(6x^2 - 3 - 5x^3) - 4x^3 -2x^2 + 8
Combine like terms
-5x^3 -4x^3 +6x^2 - 2x^2 -3 +8
-9x^3+4x^2+5
Population of England in 2003 = 383 * 130,281 = 49,897,623
In 2008 this is 0.84 * 61,000,000 = 51,240,000
Increase = 51,240,000 - 49,897,623 = 1,342,377
Answer is 1,300,000 to 2 significant figures.
