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VashaNatasha [74]
3 years ago
7

A student draws two parabolas both parabolas cross the x axis at (-4,0) and (6,0) the y intercept of the first parabolas is (0,-

12). The y intercept of the second parabola is (0,-24) what is the positive difference between the a values for the two functions that describe the parabolas
Mathematics
2 answers:
Katen [24]3 years ago
8 0

0.5

Step-by-step explanation:

faust18 [17]3 years ago
5 0

Answer:

The positive difference between the a values is 0.5

Step-by-step explanation:

we know that

Both parabolas cross the x axis at (-4,0) and (6,0)

so

The general equation is

y=a(x+4)(x-6)

<em>Find the value of a in the first parabola</em>

The y-intercept is (0,-12)

so

For x=0, y=-12

substitute

y=a(x+4)(x-6)

-12=a(0+4)(0-6)

-12=a(-24)

a=0.5

<em>Find the value of a in the second parabola</em>

The y-intercept is (0,-24)

so

For x=0, y=-24

substitute

y=a(x+4)(x-6)

-24=a(0+4)(0-6)

-24=a(-24)

a=1

<em>Find the positive difference between the a values for the two functions</em>

so

1-0.5=0.5

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3 years ago
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natta225 [31]

Answer:

y = 14

Step-by-step explanation:

∠BCF and ∠EFH are same side interior angles and are supplementary, hence

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6 0
3 years ago
At a certain pizza parlor, % of the customers order a pizza containing onions, % of the customer's order a pizza containing saus
wel

Answer:

At a certain pizza parlor,36 % of the customers order a pizza containing onions,35 % of the customers order a pizza containing sausage, and 66% order a pizza containing onions or sausage (or both). Find the probability that a customer chosen at random will order a pizza containing both onions and sausage.

Step-by-step explanation:

Hello!

You have the following possible pizza orders:

Onion ⇒ P(on)= 0.36

Sausage ⇒ P(sa)= 0.35

Onions and Sausages ⇒ P(on∪sa)= 0.66

The events "onion" and "sausage" are not mutually exclusive, since you can order a pizza with both toppings.

If two events are not mutually exclusive, you know that:

P(A∪B)= P(A)+P(B)-P(A∩B)

Using the given information you can use that property to calculate the probability of a customer ordering a pizza with onions and sausage:

P(on∪sa)= P(on)+P(sa)-P(on∩sa)

P(on∪sa)+P(on∩sa)= P(on)+P(sa)

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I hope it helps!

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3 years ago
a recent survey determained that 7 out of 9 students eat school lunch at least once a week. if 54 students were surveyed how man
Setler [38]

Answer:

12 students

Step-by-step explanation:

Given

Students = 54

Required

Determine the number of students that eat lunch once a week

In Sets;

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<em>In other words;</em>

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Number = \frac{108}{9}

Number = 12

3 0
3 years ago
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