Reflection of a function

reflection of f(x) about x-axis
So
Answer:
y = 14
Step-by-step explanation:
∠BCF and ∠EFH are same side interior angles and are supplementary, hence
5x - 66 +2x + 50 = 180
7x - 16 = 180 ( add 16 to both sides )
7x = 196 ( divide both sides by 7 )
x = 28
∠BCF = 5x - 66 = (5 × 28) - 66 = 140 - 66 = 74
∠ACD = ∠BCF ( vertical angles ), hence
9y - 52 = 74 ( add 52 to both sides )
9y = 126 ( divide both sides by 9 )
y = 14
Answer:
At a certain pizza parlor,36 % of the customers order a pizza containing onions,35 % of the customers order a pizza containing sausage, and 66% order a pizza containing onions or sausage (or both). Find the probability that a customer chosen at random will order a pizza containing both onions and sausage.
Step-by-step explanation:
Hello!
You have the following possible pizza orders:
Onion ⇒ P(on)= 0.36
Sausage ⇒ P(sa)= 0.35
Onions and Sausages ⇒ P(on∪sa)= 0.66
The events "onion" and "sausage" are not mutually exclusive, since you can order a pizza with both toppings.
If two events are not mutually exclusive, you know that:
P(A∪B)= P(A)+P(B)-P(A∩B)
Using the given information you can use that property to calculate the probability of a customer ordering a pizza with onions and sausage:
P(on∪sa)= P(on)+P(sa)-P(on∩sa)
P(on∪sa)+P(on∩sa)= P(on)+P(sa)
P(on∩sa)= P(on)+P(sa)-P(on∪sa)
P(on∩sa)= 0.36+0.35-0.66= 0.05
I hope it helps!
What's the question and are the jobs making food and bringing it to tables
Answer:
12 students
Step-by-step explanation:
Given

Required
Determine the number of students that eat lunch once a week
In Sets;
If out of 9, at least 7 eats one a week then
9 - 7 eats lunch once a week

<em>In other words;</em>
2 out of 9 students eat lunch once a week
Number of students in this category is then calculated as thus;



