Answer:
you subtracted 2y from both sides to each side getting 2y = 10x +8
Step-by-step explanation
Assume L=1.5W, where W=width, L= Length of the triangle.
Therefore,
Perimeter (P) = 2(W+L) = 2(W+1.5W) = 2(2.5W) = 5W=20 => W=20/5 = 4 in
Then, L=1.5W = 1.5*4 = 6 in
Area, A= L*W = 6*4 = 24 in^2
Y= (x(9/5)) + 32; Ex: y=(100(9/5)) + 32 —> 100 x 1.8 (or 9/5) = 180–> 180 + 32= 212 F
Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
