Question

I WILL MARK BRAINLIEST PLEASE

Answer 1

Answer:45

Step-by-step explanation:

Given

at t=0 there are 4 unpaired socks

Suppose at any instant no of unpaired socks are $N=4e^{kt}$

at t=4(months)

$N=9=4e^{4k}\\e^{4k}=\frac{9}{4}$

for t=12(months)

$N=4e^{12k}=4(e^{4k})^{3}$

$N=4\times (\frac{9}{4})^3=\frac{9^3}{4^2}\\N=45.56\approx 45\ \text{unpaired socks}$