Answer:
The length of the flagpole be 41.2 ft .
Option (A) is correct .
Step-by-step explanation:
As given
The angle looking up at the sun is 70°.
A flagpole casts a shadow of 15 ft .
Now by using the trignometric identity .



BC = 15 ft
tan 70° = 2.75 (Approx)

AB = 2.75 × 15
= 41.2 ft
Therefore the length of the flagpole be 41.2 ft .
Option (A) is correct .
If a 1L IV contains 60meq of kcal and the IV was discontinued after 400ml has infused, then the amount of IV received by the patient is 24meq of kcal.
Calculation for the Amount of IV
It is given that,
1L IV contains 60meq of kcal
⇒ 1000 mL of IV contains 60meq of kcal
⇒ 1 mL of IV will contain 60 / 1000 meq of kcal
As per the question,
The amount of IV infused in the patient = 400 mL
⇒ The amount of IV received by the patient in meq of kcal = 400 × (60 / 1000)
= 4 × 6
= 24 meq of kcal
Hence, the patient receives 24meq of kcal amount of IV.
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Answer:
5 times as many should be your answer.
Answer:
.
Step-by-step explanation:
I tried to solve this but I don't get it maybe use another app for it bc it looks hard lolz
The number of viruses was 4000 times greater than number of protozoa.
Step-by-step explanation:
Given,
Number of protozoa = 
Number of viruses = 
Let,
x be the number of times number of viruses is greater than number of protozoa.
Number of viruses = Number of time * Number of protozoa

Dividing both sides by 

The number of viruses was 4000 times greater than number of protozoa.
Keywords: division, scientific notation
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