Answer:
16n
Add the coefficients and leave the variables
Answer:
26=x
Step-by-step explanation:
The value of L4 and R4 over [0,7] for the function f(x) = 6x² will be 2[2√0 + 2√2 + 2√4 + 2√6] and 2[2√2 + 2√4 + 2√6 + 2√8] respectively.
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
It is given that the function is,
I'm assuming that you mean the left and right Riemann sums with four equal subintervals when you refer to L4 and R4.
If so, then Δx = (8-0)/4 = 2, and f(x) = 2√x.
L4 = f(0)Δx + f(2)Δx + f(4)Δx + f(6)Δx
L4 =2[2√0 + 2√2 + 2√4 + 2√6]
R4 = 2[2√2 + 2√4 + 2√6 + 2√8]
Thus, the value of L4 and R4 over [0,7] for the function f(x) = 6x² will be 2[2√0 + 2√2 + 2√4 + 2√6] and 2[2√2 + 2√4 + 2√6 + 2√8] respectively.
Learn more about the function here:
brainly.com/question/5245372
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The <u>correct answer</u> is:
You can map ABC to A'B'C' by translating it 6 units left and reflecting it across the x-axis, which is a series of rigid motions.
Explanation:
In ABC, the coordinates are:
A(1, -3)
B(5, 3)
C(4, -1).
In A'B'C', the coordinates are:
A'(-5, 3)
B'(-1, -3)
C'(-2, 1)
Each point is mapped to its image:
A(1, -3)→A'(-5, 3)
B(5, 3)→B'(-1, -3)
C(4, -1)→C'(-2, 1)
Comparing the x-coordinates in the pre-image and image, we notice that the image has an x-coordinate that is 6 less than that of the pre-image:
1-6 = -5
5-6 = -1
4-6 = -2
This means that the figure must be translated 6 units left; that is the only way to have this change on the pre-image to form the image.
Comparing the y-coordinates of the pre-image with those of the image, we notice that they are negated:
-(-3) = 3
-(3) = -3
-(-1) = 1
This means the pre-image was reflected across the x-axis; this is the only way to negate the y-coordinate and not change the x-coordinate.
These are rigid motions because they do not change the shape or size, they simply move it and change its orientation.
You write .63/1 or (63/100) but since you can't really do anything with that, you move the decimals so that it's a whole number but you have to move the decimal the same amount of times with the one. So since you move 2 times so that it's 63, you do the same with the one=100. So the answer is 63/100
