Area of circle=Πrsquare
A=Πx5x5
A=78.5
Area of rect 10x9=90
Tsurface =168.5
Answer:
it would be subtraction
Step-by-step explanation:
Because if you are trying to get you would do 2-2 to get 0 and have x by itself
Answer:
False
Step-by-step explanation:
Given
![XLIV = 64](https://tex.z-dn.net/?f=XLIV%20%3D%2064)
Required
True or False
The above numeral can be split as follows:
![XLIV = XL + IV](https://tex.z-dn.net/?f=XLIV%20%3D%20XL%20%2B%20IV)
X means 10 and L means 50.
But because X (10) which is smaller comes before L (50), XL is executed as:
![XL = -10 + 50](https://tex.z-dn.net/?f=XL%20%3D%20-10%20%2B%2050)
![XL = 40](https://tex.z-dn.net/?f=XL%20%3D%2040)
In Roman numerals;
![IV = 4](https://tex.z-dn.net/?f=IV%20%3D%204)
Substitute 40 for XL and 4 for IV.
![XLIV = 40 + 4](https://tex.z-dn.net/?f=XLIV%20%3D%2040%20%2B%204)
![XLIV = 44](https://tex.z-dn.net/?f=XLIV%20%3D%2044)
Hence;
<em />
<em> is false</em>
<span>When you add fractions, the denominators must be the same, so you may have to generate equivalent fractions by using the lowest common multiple of all the denominators. For subtraction of fractions, you use the same method. When multiplying fractions, you can only multiply the numerators together, and the denominators together. </span>
The formula is y-y0=m(x-x0)
So we plug in the Y's and the X's given:
-5-9=m(0-(-3)) >>>> -14=m(3)>>>>> m=-14/3
The next formula is y=mx+b , choose any point to use for X and Y: I'm gonna choose (0,-5)
-5=-14/3(0)+b >>> b=-5
Your formula is: y=-14/3x-5