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3 years ago

Choose the correct answer below.

Mathematics

1 answer:

Elodia [21]3 years ago

3 0

Answer:

Step-by-step explanation:

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Solve 0.05p-0.02(5-2p)=0.05(p-2)-0.12

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$0.05p-0.02(5-2p)=0.05(p-2)-0.12$

$0.05p-0.02(5-2p)=0.05(p-2)-0.12:p$

$
0.05p-0.1+0.04p=0.05p-0.1-0.12
 
$ $|Expand \ the \ equation|$

$0.09p-0.1=0.05p-0.1-0.12
 
$

$0.09p-0.1=0.05p-0.22$

$
0.09p-0.1-0.05p=-0.22
 

$ $|Subtract \ 0.05p \ from \ both \ sides|$

$
0.04p-0.1=-0.22
 
$

$
0.04p=-0.22+0.1
 
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$
0.04p=-0.12
 
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3 years ago

PLEASE HELP WILL GIVE TWENTY POINTS Which is the best approximation for the measure of angle ABC?

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Cos(x) = BC/AB = 10.5/20 = 0.525 ⇒ x = 58.3°

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3 years ago

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3 years ago

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A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank

harkovskaia [24]

Answer:

The value is $P_o = \$ 561958.9$

Step-by-step explanation:

From the question we are told that

The capacity of the metal tank is $C = 2000 \ gallon$

The duration usage is $t = 15\ years \ ago$

The cost of 2000-gallon tank 15 years ago is $P = \$100,000$

The capacity of the second tank considered is $C_1 = 5,000$

The power sizing exponent is $e = 0.57$

The initial construction cost index is $u_1 = 180$

The new construction after 15 years cost index is $u_2 =600$

Equation for the power sizing exponent is mathematically represented as

$\frac{P_n}{P} = [\frac{C_1}{C} ]^{e}$

=> Here $P_n$ is the cost of 5,000-gallon tank as at 15 years ago

$P_n = [\frac{5000}{2000} ] ^{0.57} * 100000$

$P_n = \$168587.7$

Equation for the cost index exponent is mathematically represented as

$\frac{P_o}{P_n} = \frac{u_2}{u_1}$

Here $P_o$ is the cost of 5,000-gallon tank today

$\frac{P_o}{168587.7} = \frac{600}{180}$

=> $P_o = \frac{600}{180} * 168587.7$

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3 years ago

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