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2 years ago

A cylinder has a radius of 3 in and a volume of approximately 136.78 in? What is the height of the cylinder?

Mathematics

1 answer:

Aleonysh [2.5K]2 years ago

7 0

Answer:

4.835(I don't know unit.(m/in/cm)

Step-by-step explanation:

volume=πr^2h

136.78=22÷7×3^2×h

h=136.78×7÷(22×9)=4.835

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Given that these simultaneous equations

Tatiana [17]

The value of k is $(3\sqrt{ 10})/2$

<h3>How to solve the simultaneous equation?</h3>

Given:

x-y=k.............(eq i)

2x²+y²-15..............(eq ii)

We would make y the subject formula in eq ii

2x²+y²-15= 0

2x² + y²= 15

y²= 15-2x²

y= $\sqrt{15-2x^2}$ ...........(eq iii)

Substitute the value of y into eq i

x-( $\sqrt{15-2x^2}$ = k

x- ( $\sqrt{15} - 2x$ = k

k= $(3\sqrt{ 10})/2$

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1 year ago

Y^10+7y^5-8<br> Factor completely

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(y^5-1)(y^5+8)............

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2 years ago

four friends bought 10 lbs of nuts and shared them equally. How many pounds if nuts did each friend get

Marianna [84]

You need to do 10 divided by 4. Each friend would get 2.5 pounds of a nut.

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3 years ago

Listed below are speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, California (based on data from SigAlert

adell [148]

Answer:

Option (B) is the correct answer to the following question.

Step-by-step explanation:

Step-1: We have to find the Mean of the series.

The series is Given in the question 62 61 61 57 61 54 59 58 59 69 60 67.

$Mean(\overline{x})=\frac{62+61+61+57+61+54+59+58+59+69+60+67}{12}$ $= 60.67$

Step-2: We have to find the Standard Deviation.

Let Standard Deviation be x.

Formula of Standard Deviation is: $s= \sqrt{\frac{\sum(x_{i}+\overline{x})}{n-1}}$

Put value in formula of Standard Deviation,

$s= \sqrt{\frac{(62+60.67)^{2}+(61+60.67)^{2}+(61+60.67)^{2}+(57+60.67)^{2}+....(67+60.67)^{2}}{n-1}}$ = 40.75

Step-3: Then, we have to find the critical value by chi-square.

$X_{1-\alpha/2}^{2}=3.82$

$X_{1-\alpha/2}^{2}=21.92$

Then, find the confidence interval which is 95%.

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{21.92}.(4.075)^2 }\approx2.8868 \\ i.e 2.9$

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{3.816}.(4.075)^2 }\approx6.9188 \\ i.e 6.9$

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3 years ago

Solve the problem c=3.14d for d

Maksim231197 [3]

Answer:

$c = 3.14d \\ d = \frac{c}{3.14}$

It's change of subject. :)

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2 years ago