Use the distributive property to writer an equivalent expression 2(w + 6x)

The length of a side of a triangle is 26 in. A line, parallel to the given side ,divides the triangle into 2 parts of equal area

Ugo [173]

Answer:

13 $\sqrt{2}$

7 0

3 years ago

Read 2 more answers

What's 2 - 4 + 3 ×2 Pls solve this quick

Triss [41]

Answer:

4

Step-by-step explanation:

3x2 is 6

2-4 is -2

6-2 is 4

8 0

2 years ago

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1.Encuentra la ecuación de la circunferencia que tiene como ecuación ordinaria (x-4)² + (y+5)²= 25 2- encuentra la ecuación gene

rodikova [14]

Responder:

1) x² + y²-8x + 10y + 16 = 0

2) x² + y² + x + 18y + 33 = 0

Explicación paso a paso:

A partir de la pregunta, debemos expresar la ecuación en la forma estándar de un círculo expresado como;

x² + y² + 2gx + 2fy + c = 0 donde;

(-g, -f) es el centro.

1) Para la ecuación (x-4) ² + (y + 5) ² = 25

Expande el paréntesis;

(x-4) ² + (y + 5) ² = 25

x²-8x + 16 + y² + 10x + 25 = 25

x²-8x + 16 + y² + 10y + 25-25 = 0

Recopile términos similares;

x² + y²-8x + 10y + 16 + 0 = 0

x² + y²-8x + 10y + 16 = 0

Por lo tanto, la ecuación requerida es x² + y²-8x + 10y + 16 = 0

2) Para la expresión (x + 1) ² + (y + 9) ² = 49

x² + x + 1 + y² + 18y + 81 = 49

x² + x + 1 + y² + 18y + 81-49 = 0

Recopile términos similares;

x² + y² + x + 18y + 82-49 = 0

x² + y² + x + 18y + 33 = 0

Por tanto, la ecuación requerida es x² + y² + x + 18y + 33 = 0

4 0

3 years ago

The college basketball team at west texas state university has 10 players; 5 are seniors, 2 are juniors, and 3 are sophomores. t

Tanya [424]

I believe it's 5 out of 10

5 0

3 years ago

Find the second partial derivatives of the following functions

artcher [175]

(a) z = 3x ² - 4xy + 15y ²

has first-order partial derivatives

∂z/∂x = 6x - 4y

∂z/∂y = -4x + 30y

and thus second-order partial derivatives

∂²z/∂x ² = 6

∂²z/∂x∂y = -4

∂²z/∂y∂x = -4

∂²z/∂y ² = 30

where ∂²z/∂x∂y = ∂/∂x [∂z/∂y] and ∂²z/∂y∂x = ∂/∂y [∂z/∂x].

(b) z = 4x eʸ

∂z/∂x = 4eʸ

∂z/∂y = 4x eʸ

∂²z/∂x ² = 0

∂²z/∂x∂y = 4eʸ

∂²z/∂y∂x = 4eʸ

∂²z/∂y ² = 4x eʸ

(c) z = 6x ln(y)

∂z/∂x = 6 ln(y)

∂z/∂y = 6x/y

∂²z/∂x ² = 0

∂²z/∂x∂y = 6/y

∂²z/∂y∂x = 6/y

∂²z/∂y ² = -6x/y ²

6 0

3 years ago